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3 years ago

9

You go to the store to buy icecream. The icecream comes in a cylindrical tub that has a diameter of 5 inches and is 4 inches tal

l.
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1 answer:

telo118 [61]3 years ago

5 0

Answer:78.5

Step-by-step explanation:

First you find the volume of a cylinder then you plug in the answers don't forget that to find the radius you do diameter divided by 2

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Now for the top make it drop its the wap

Shalnov [3]

Answer:

get the bucket get the mop it's a way it's a wap

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2 years ago

Read 2 more answers

Write an algebraic expression for the following word phrase 9.94 less than the product of 26 and x

goblinko [34]

Answer:

the answer is 26x - 94

8 0

2 years ago

2x - 3y = 12<br> x = 4y + 1

aliya0001 [1]

Answer:

x = 9, y = 2 is the solution of the given system.

Step-by-step explanation:

Here, the given set of equation is :

2 x - 3 y = 12

x = 4 y + 1

Now, from equation (2) we see that x = 4 y + 1.

Substitute the value of y from (2) in the first equation. we get:

2 x - 3 y = 12 ⇒ 2 (4 y + 1) - 3 y = 12

or, 8 y + 2 - 3 y = 12

or, 5 y = 12- 2 = 10

or, y = 10/ 5 = 2

or, y = 2

Now, x = 4 y + 1 ⇒ x = 4(2) + 1 = 8 + 1 = 9, or x = 9

Hence, x = 9, y = 2 is the solution of the given system.

5 0

3 years ago

Find the LCD of the fractions, and then simplify the expression. Assume that no denominator equals zero. 5/(3x^2y) - 4/(6xy^3

tamaranim1 [39]

The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)

now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-

5(2y^2) - 4(x)
------------------
6x^2y^3

= 2( 5y^2 - 2x)
-----------------
6x^2y^3

= 5y^2 - 2x
-----------
3x^2y^3

5 0

3 years ago

Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24

S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

$\frac{4}{3}=\frac{32}{d}$

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable $d$ and see if it satisfies the equation.

1) $d=22$

$\frac{4}{3}=\frac{32}{22}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 2}{22\div 2}$

$\frac{4}{3}=\frac{16}{11}$

The above statement can never be true and hence 22 is not a solution.

2) $d=23$

$\frac{4}{3}=\frac{32}{23}$

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) $d=24$

$\frac{4}{3}=\frac{32}{24}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 8}{24\div 8}$

$\frac{4}{3}=\frac{4}{3}$

The above statement is always true and hence 24 is a solution.

4) $d=25$

$\frac{4}{3}=\frac{32}{25}$

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

4 0

3 years ago