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Andreas93 [3]
2 years ago
14

Can you tell me how to factorise 6b+24bc

Mathematics
2 answers:
Kamila [148]2 years ago
3 0
When we factorise an expression, we are looking for simple factors that multiply to get the original expression. Usually it is very natural to factorise something like a quadratic in x. For example:

x^2 + 3x + 2 = (x+1)(x+2)

But there are other situations where factorisation can be applied. Take this quadratic:

x^2 - 9x = x(x-9)

This second example is closer to the question in hand. Just like x was a common factor to both x^2 and -9x, we are looking for a common factor to both 6b and 24bc. The common factor is 6b.

Hence 6b + 24bc = 6b(1 + 4c).

I hope this helps you :)
Ne4ueva [31]2 years ago
3 0
It would equal 30bbc I think,  but I dont know how to factorize it maybe learn how to factorize on youtube.
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Answer:

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Step-by-step explanation:

When you need to factor a quadratic, and the coefficient of the x² is not 1, use the slide and divide method.

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Factor:  10x² + 11x + 3

Here a = 10, b = 11, and c = 3

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Step 2:    Factor this   (this step will always factor)

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So the factors are  (x + 5)(x + 6), but we now need to DIVIDE by a, since we multiplied it into c before.  We divide the constants in the factors...

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Now reduce the fractions as much as possible...

(x + 1/2 )(x + 3/5)

*If they don't reduce to a whole number, SLIDE the denominator over as a coefficient of x....

(2x + 1)(5x + 3)        *2 slide over in front of x, 5 slide over in front of x, the fractions are gone!

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