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3 years ago

What is the diference between a terminating decimal and repeating decimal .

Mathematics

1 answer:

dangina [55]3 years ago

8 0

Answer:

A repeating decimal is a decimal with no end, its constantly repeating itself

A terminating decimal is a decimal with an end

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To get to the next term in this sequence, multiply the last term by 2.5. What is the value of the next term?

larisa86 [58]

Answer:

39.0625

Step-by-step explanation:

15.625 times 2.5= 39.0625

You're just multiplying each value by 2.5

1 times 2.5= 2.5

2.5 times 2.5= 6.25

6.25 times 2.5= 15.625

and then 15.625 times 2.5= 39.0625

8 0

2 years ago

Data was collected for a sample of organic snacks. The amount of sugar (in mg) in each snack is summarized in the histogram belo

Blababa [14]

Answer:

The sample size for the data set = 56

Step-by-step explanation:

The sample size or number of individuals (n) is gotten from a histogram by summing up the total frequencies of occurrences.

In this example, the frequencies are: 2 4 6 8 10 12 14

Therefore, the sample size (n) is calculated as follows:

n = 2 + 4 + 6 + 8 + 10 + 12 + 14 = 56

Therefore the sample size for the data set = 56

6 0

4 years ago

Find the sum of the equation

stealth61 [152]

Answer:

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

Step-by-step explanation:

1) Rewrite ${y}^{2}-2y+1y$ in the form ${a}^{2}-2ab+{b}^{2}$ , where a = y and b = 1.

$\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}$

2) Use Square of Difference: ${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$ .

$\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}$

3) Factor ${y}^{2}+6y-7$ .

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

$(y-1)(y-7)$

Outcome/Result: $\frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}$

4) Rewrite the expression with a common denominator.

$\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}$

5) Expand.

$\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}$

6) Collect like terms.

$\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}$

7) Simplify ${y}^{2}+(7y+6y)-6y$ to ${y}^{2}+13y-6y$

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

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2 years ago

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3 years ago

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kicyunya [14]

Answer is -1/2 or -0.5

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3 years ago

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