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Julli [10]
2 years ago
11

What second degree polynomial function has a leading coefficient of -2 and root 4 with a multiplicity of 2

Mathematics
1 answer:
OverLord2011 [107]2 years ago
8 0

The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

<h3>How to write the polynomial?</h3>

A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

p(x) = a*(x - x_1)*(x - x_2)*...*(x - x_n)

Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.

Then this polynomial is equal to:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

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On a map, 2 cm represents 30 mi. The actual distance between two towns
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Answer:

<h2>5 cm</h2>

Step-by-step explanation:

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step one:

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2 years ago
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Scorpion4ik [409]
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6 0
3 years ago
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Can someone help me with questions 2 and 3 pls?
bija089 [108]

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3 years ago
15/4 divided by -5/8 equals?
kolezko [41]

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15/4 ÷ -5/8

Copy dot flip

15/4 * -8/5

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