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Julli [10]
2 years ago
11

What second degree polynomial function has a leading coefficient of -2 and root 4 with a multiplicity of 2

Mathematics
1 answer:
OverLord2011 [107]2 years ago
8 0

The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

<h3>How to write the polynomial?</h3>

A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

p(x) = a*(x - x_1)*(x - x_2)*...*(x - x_n)

Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.

Then this polynomial is equal to:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

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What is the midpoint of a line segment with the endpoints (-4,-3) and (7,-5)?O A. (-3.5, 1)O B. (1.5,-4)O c. (-4,1.5)O D. (1.-3.
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SOLUTION:

Step 1:

In this question, we are given the following:

What is the midpoint of a line segment with the endpoints (-4,-3) and (7,-5)?

A. (-3.5, 1)

B. (1.5,-4)

C. (-4,1.5)

D. (1.-3.5)

Step 2:

The midpoint of a line segment with the endpoints (-4,-3) and (7,-5) is:

\begin{gathered} (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ =\text{ (}\frac{-4+7}{2},\frac{-3+(-5)}{2}) \\ =\text{ (}\frac{3}{2},\frac{-8}{2}) \\  \end{gathered}

=\text{ (1. 5 , -4 ) --- OPTION B}

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