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Julli [10]
2 years ago
11

What second degree polynomial function has a leading coefficient of -2 and root 4 with a multiplicity of 2

Mathematics
1 answer:
OverLord2011 [107]2 years ago
8 0

The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

<h3>How to write the polynomial?</h3>

A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

p(x) = a*(x - x_1)*(x - x_2)*...*(x - x_n)

Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.

Then this polynomial is equal to:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

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What are the x-intercepts of this quadratic function? g(x) = -2(x − 4)(x + 1) A. (4,0) and (-1,0) B. (-4,0) and (-1,0) C. (4,0)
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Answer:

Option A. (4,0) and (-1,0)

Step-by-step explanation:

we know that

The equation of a vertical parabola in factored form is equal to

f(x)=a(x-x_1)(x-x_2)

where

a is a coefficient

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In this problem we have

g(x)=-2(x-4)(x+1)

we have

a=-2

The leading coefficient is negative, that means the parabola open downward

The zeros of the function are

x_1=4\\x_2=-1

Remember that the x-intercepts are the values of x when the value of the function is equal to zero

therefore

The x-intercepts are (4,0) and (-1,0)

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Explanation:-

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2. HL can be a reason to show given triangles are congruent as the triangles are right triangle with equal legs and hypotenuse.

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4. LA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

5. AAS  cannot be a reason to show given triangles are congruent as it is not given that they have two angles common in both the triangles.

6.SSS can be a reason to show given triangles are congruent as it is shown that all the sides of one triangle is congruent to the other.

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The <u>correct answer</u> would most likly be C. Triangle JKL is similar to triangle RST.

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