Answer:
B
Explanation:
The last 2 answers can immediately be cancelled out as they're not combustion of ethanol, combustion in this context is not a reversable reaction so cannot be referenced in this way.
The answer is determined to be B just by simply counting the numbers of each of the elements on the reactants (left) side and the products (right) side and ensuring they're the same
In A on the reactants side there is 2C 6H 3O and on the products side there is 1C 3O and 2H its not equal so it is not correct
In B on the reactants side there is 2C 6H 7O and on the products side there is 2C 6H 7O its equal so this answer is correct
Volume of a cylinder: V= pi (r)^2(h)
The concentration of in the stack gas = 12 ppmv
That means 12 L of is present per
The given temperature is 273 K (0 C) and pressure is 1 atm. At these conditions, 1 mol of gas would occupy,
V = 22.4 L
1 mol occupies 22.4 L
Moles of =
Mass of = =μg
Converting :
=
Calculating the concentration in μg/:
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Answer:
6.6253*10²¹molecules of ethane (C₂H₆) are present in 0.334 g of C₂H₆
Explanation:
Avogadro's Number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance. Its value is 6.023 * 10²³ particles per mole. Avogadro's number applies to any substance.
In this case, being:
the molar mass of ethane C₂H₆ is:
C₂H₆: 2*12 g/mole + 6* 1 g/mole= 30 g/mole
Then you can apply the following rule of three: if 30 grams of C₂H₆ are present in 1 mole, 0.334 grams of C₂H₆ in how many moles are present?
moles of C₂H₆=0.011
Finally, taking into account the definition of Avogadro's number, you can apply the following rule of three: if there are 6.023 * 10²³ molecules of C₂H₆ in 1 mole, how many molecules are there in 0.011 moles?
molecules of C₂H₆= 6.6253*10²¹
<u><em>6.6253*10²¹molecules of ethane (C₂H₆) are present in 0.334 g of C₂H₆</em></u>