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Mekhanik [1.2K]
3 years ago
9

Determine which of the following elements would lose electrons when becoming ions:

Chemistry
1 answer:
Artemon [7]3 years ago
5 0

Answer:

I, III, and V  

Explanation:

All five options are correct.

However, your instructor is probably expecting the answer I, III, and V.

These three elements are on the left-hand side of the Periodic Table. Thus, they tend to lose electrons and form positive ions most easily.

H is the most reluctant to form a cation. Its first ionization energy is 1100 kJ·mol⁻¹.

However, F and He can lose electrons to form cations.

It takes only 1700 kJ·mol⁻¹ to remove an electron from F. However, F tends to add electrons to get a complete valence shell.

Even He, with a complete valence shell, will give up a valence electron for the expenditure of only 2400 kJ·mol⁻¹.

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1023 molecules or atoms depending on substance
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3 years ago
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What color does copper produce when it reacts to chlorine
kiruha [24]

The color it produces is Bright green.

6 0
3 years ago
A buffer solution is composed of 4.00 4.00 mol of acid and 3.25 3.25 mol of the conjugate base. If the p K a pKa of the acid is
Reika [66]

<u>Answer:</u> The pH of the buffer is 4.61

<u>Explanation:</u>

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{conjuagate base}]}{[\text{acid}]})

We are given:

pK_a = negative logarithm of acid dissociation constant of weak acid = 4.70

[\text{conjuagate base}]} = moles of conjugate base = 3.25 moles

[\text{acid}]  = Moles of acid = 4.00 moles

pH = ?

Putting values in above equation, we get:

pH=4.70+\log(\frac{3.25}{4.00})\\\\pH=4.61

Hence, the pH of the buffer is 4.61

8 0
3 years ago
A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water level rose to the 37.4 mL mark
musickatia [10]
Volume of the metal = change in volume reading
Volume = 37.4 - 33
Volume = 4.4 ml

Density = mass / volume
Density = 7.101 / 4.4
Density = 1.61 g/ml
7 0
3 years ago
Determine the maximum amount of Fe that was produced during the experiment. Explain how you determined this amount.
dsp73

Answer:

5 moles of Fe

Explanation:

The equation of the reaction is;

2 Al(s) + Fe 2O 3(s) --> 2Fe (s) + Al 2O 3 (s)

Now;

1 mole of Fe2O3 require 2 moles of Al

3 moles of Fe2O3 requires 3 × 2/1 = 6 moles of Al

Hence Al is the limiting reactant.

If 2 moles of Al yields 2 moles of Fe

5 moles of Al yields 5 × 2/2 = 5 moles of Fe

5 0
3 years ago
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