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erastova [34]
2 years ago
11

Each of the following names is wrong. Draw structures based on them, and correct the names:(b) 1,1,1-trimethylheptane

Chemistry
1 answer:
devlian [24]2 years ago
5 0

The correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

<h3>IUPAC NAME:</h3>

It is systematic way of nomenclature of organic compounds.

It is based on the position of functional groups, preference of the functional group, long or short chain of carbon, preference of double bond, single and triple bond, branching of carbon chain, etc.

The given compound is 1,1,1-trimethylheptane.

The given name is wrong according to IUPAC name because the numbering of carbon atom should be done in that way in which the carbon atom chain is largest.

Here, in this case the numbering is done from right side. Thus the largest carbon chain have 8 carbon atom.

If the numbering is done according to the question, number of carbon atom in straight chain is 7.

Thus, we concluded that the Correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

learn more about Nomenclature:

brainly.com/question/14094007

#SPJ4

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Answer:

C.106 ml

Explanation:

Boyle's Law P₁V₁ = P₂V₂ , but we need to make sure our pressure is in the same units, in this case we will convert torr to atm

811 torr * (1atm/760torr) = 1.067105263 atm

P₁V₁ = P₂V₂

(1.067105263 atm)(11.1 mL) = (0.112 atm)(V₂)

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V₂ = 105.7577538 mL = 106 mL

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6 0
3 years ago
2. Which of these items would allow one scientist to reproduce the experiment of another scientist.
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Answer:

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8 0
3 years ago
Give the value of the quantum number ℓ, if one exists, for a hydrogen atom whose orbital angular momentum has a magnitude of 6√(
MakcuM [25]

Answer:

For this angular momentum, no quantum number exist

Explanation:

From the question we are told that

   The magnitude of the angular momentum is  L  = 6\sqrt{\frac{h}{2 \pi} }

The generally formula for Orbital angular momentum is mathematically represented as

           L  = \sqrt{(l * (l + 1)) } *  \frac{h}{2 \pi}

Where l is the quantum number

now  

We can look at the given angular momentum in this form as

      L  = 6\sqrt{\frac{h}{2 \pi} }    =  \sqrt{36}  * \sqrt{\frac{h}{2 \pi}} }

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5 0
4 years ago
Fill in the blanks.
vichka [17]

Answer:

Hello There!!

Explanation:

1.C nH 2n

2.Family

3.carbonyl group

4.Catalyst

5.Nickel

hope this helps,have a great day!!

~Pinky~

4 0
3 years ago
Read 2 more answers
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