Ask question

Ask question

All categories

3 years ago

13

The expected lifetime of a television is 18 years with a standard deviation of 4. Use Chebychev's inequality to estimate the pro

bability that television will last between 9 and 27 years.a) 0.2435b) 0.1975c) 0.7334d) 0.8025e) 0.8504f) None of the above.

1 answer:

My name is Ann [436]3 years ago

6 0

Answer E

Step-by-step explanation:

use Caculator very easy please dont ask

You might be interested in

The volume of the cylinder is 5275 ft and the height is 23 find the diameter please explain this is for school tomorrow

stepan [7]

$\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} V=5275\\ h=23 \end{cases}\implies 5275=\pi r^2(23)\implies \cfrac{5275}{23\pi }=r^2 \\\\\\ \sqrt{\cfrac{5275}{23\pi }}=r\implies 15.144\approx r~\hspace{10em}\stackrel{diameter=2r}{d\approx 30.288}$

4 0

3 years ago

Can someone pls help me

olga55 [171]

32-20 = 12

14-2 = 12

so the input is 12 more than the output

so 6+12 = 18

and

-10-12 = -22

4 0

4 years ago

Read 2 more answers

12 divided by x = 50

olga2289 [7]

the answer to 12 divided by 50 calculated using Long Division is:

0

12 Remainder

7 0

3 years ago

Read 2 more answers

What is the image point of (-7,0) after a translation left 4 units and up 1 unit?<br><br>

snow_tiger [21]

Answer:

(-11, 1)

Step-by-step explanation:

moving to the left by 4 means -7 - 4 = -11

up one unit changes the 0 to 1

5 0

4 years ago

The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th

makvit [3.9K]

Answer:

<u><em>k = 0.2645</em></u>

Step-by-step explanation:

Given model:

y = 4070 $e^{kt}$

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070 $e^{3k}$

$\frac{9000}{4070}$ = $e^{3k}$

$\frac{900}{407}$ = $e^{3k}$

<u><em>Taking natural logarithm on both sides, we get:</em></u>

$ln\frac{900}{407}$ = $ln(e^{3k})$

$ln\frac{900}{407}$ = 3k ln<em>e</em>

ln<em>e</em>=1

$ln \frac{900}{407}$ = 3k

or k = $\frac{1}{3}$ $ln\frac{900}{(407)}$

k = $\frac{1}{3}$ (0.7936)

<em>k = 0.2645</em>

<em />

7 0

3 years ago