<img src="https://tex.z-dn.net/?f=-5x-16%2B9x%2Bx-1" id="TexFormula1" title="-5x-16+9x+x-1" alt="-5x-16+9x+x-1" align="absmiddle

1. The current in a clothes washer is 15A when plugged into a 120V outlet. What is

mylen [45]

Answer:

Step-by-step explanation:

Power = Force × Velocity.

15*120=1800

7 0

3 years ago

In the diagram, what is mZVSR?

sesenic [268]

Answer:

80 degrees.

180-100=80

hope that helps

Please said thanks

5 0

3 years ago

Distance between two ships At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (naut

frozen [14]

Answer:

a) $\sqrt{144-288t+208t^2}$ b.) -12knots, 8 knots c) No e) $4\sqrt{13}$

Step-by-step explanation:

We know that the initial distance between ships A and B was 12 nautical miles. Ship A moves at 12 knots(nautical miles per hour) south. Ship B moves at 8 knots east.

a)

We know that at time t , the ship A has moved $12\dot t (n.m)$ and ship B has moved $8\dot t (n.m)$ . We also know that the ship A moves closer to the line of the movement of B and that ship B moves further on its line.

Using Pythagorean theorem, we can write the distance s as:

$\sqrt{(12-12\dot t)^2 + (8\dot t)^2}\\s=\sqrt{144-288t+144t^2+64t^2}\\s=\sqrt{144-288t+208t^2}$

b)

We want to find $\frac{ds}{dt}$ for t=0 and t=1

$\sqrt{144-288t+208t^2}|\frac{d}{dt}\\\\\frac{ds}{dt}=\frac{1}{2\sqrt{144-288t+208t^2}}\dot (-288+416t)\\\\\frac{ds}{dt}=\frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\\frac{ds}{dt}(0)=\frac{208\dot 0-144}{\sqrt{144-288\dot 0 + 209\dot 0^2}}=-12knots\\\\\frac{ds}{dt}(1)=\frac{208\dot 1-144}{\sqrt{144-288\dot 1 + 209\dot 1^2}}=8knots$

c)

We know that the visibility was 5n.m. We want to see whether the distance s was under 5 miles at any point.

Ships have seen each other = $s\leq 5\\\\\sqrt{144-288t+208t^2}\leq 5\\\\144-288t+208t^2\leq 25\\\\199-288t+208t^2\leq 0$

Since function $f(x)=199-288x+208x^2$ is quadratic, concave up and has no real roots, we know that $199-288x+208x^2>0$ for every t. So, the ships haven't seen each other.

d)

Attachedis the graph of s(red) and ds/dt(blue). We can see that our results from parts b and c were correct.

e)

Function ds/dt has a horizontal asympote in the first quadrant if

$\lim_{t \to \infty} \frac{ds}{dt}$

So, lets check this limit:

$\lim_{t \to \infty} \frac{ds}{dt}=\lim_{t \to \infty} \frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\=\lim_{t \to \infty} \frac{208-\frac{144}{t}}{\sqrt{\frac{144}{t^2}-\frac{288}{t}+208}}\\\\=\frac{208-0}{\sqrt{0-0+208}}\\\\=\frac{208}{\sqrt{208}}\\\\=4\sqrt{13}$

Notice that:

$4\sqrt{13}=\sqrt{12^2+5^2}$ =√(speed of ship A² + speed of ship B²)

5 0

3 years ago

Widget Wonders produces widgets. They have found that the cost, c(x), of making x widgets is a quadratic function in terms of x.

AnnyKZ [126]

The total cost of producing 6 widgets is $24 if the company also discovered that it costs $16 to produce 2 widgets, $18 to produce 4 widgets, and $48 to produce 10 widgets.

<h3>What is a quadratic equation?</h3>

Any equation of the form $\rm ax^2+bx+c=0$ where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

$\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}$

Let's suppose the quadratic function is:

c(x) = ax² + bx + c

Plug c(x) = $16

x = 2

16 = 4a + 2b + c ...(1)

Plug c(x) = $18

x = 4

18 = 16a + 4b + c ...(2)

Plug c(x) = $48

x = 10

48 = 100a + 10b + c ...(3)

After solving equations (1), (2), and (3) by substitution method:

a = 0.5

b = -2

c = 18

c(x) = 0.5x² -2x + 18

Plug x = 6 widgets:

c(6) = 0.5(36) - 12 + 18 = $24

Thus, the total cost of producing 6 widgets is $24 if the company also discovered that it costs $16 to produce 2 widgets, $18 to produce 4 widgets, and $48 to produce 10 widgets.

Learn more about quadratic equations here:

brainly.com/question/2263981

#SPJ1

5 0

2 years ago

How do you round to two decimal places ?? i just have the normal answers btw. asap!! :(

Evgen [1.6K]

Answer:

Step-by-step explanation:

Look at the 3rd decimal digit (the digit after the hundredths).

if it is the digit is less than 5 then round the number down by taking away the decimal point of the number after the 2nd decimal place;

However if it is 5 or more then round the number up by adding one on to the hundredths digit and removing the rest of the decimal part of the number after it

For example,4.749 rounds up to 4.75 because the 3rd decimal digit is a 9.

I hope this helps ^^

8 0

3 years ago