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Ghella [55]
3 years ago
11

Which of the following are solutions to the equation tan^2x-3=0? Check all that apply.

Mathematics
2 answers:
sveticcg [70]3 years ago
4 0
Tehehevebd d d dhebrbrhrbr D is the answer
faust18 [17]3 years ago
3 0

Answer:

A), B) and D)

Step-by-step explanation:

tan²x - 3 = 0

tan²x = 3

tan x = ± √3

If tan x = + √3:

x = π/3 and x = 4π/3

If tan x = - √3:

x = 2π/3 and x = 5π/3

Then, Alternatives A), B) and D are true. C is false.

I hope I've helped you.

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schepotkina [342]

Answer:

the answer is 5/6

Step-by-step explanation:

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3 years ago
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What does the 75th term look like of 6,9,12
leva [86]

Answer:

228

Step-by-step explanation:

We are adding 3 each time so general rule is

Tn= 3n + 3

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T= 3(75)+3

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olya-2409 [2.1K]
The first one is isolate the 2nd and 3rd wat r the examples
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Shiva brought $37.00 to the art supply store. She bought a brush, a sketchbook, and a paint set. The brush was 1 3 as much as th
marissa [1.9K]

Answer:

b= 3.5

s= 10.5

p=21

Step-by-step explanation:

b for brush

s for sketch book

p for paint set

b=1/3s

s= 1/2 p

b+s+p=37-2

1/3 s +s+2 s =35

1/3 s +s +2 s =35

10/3 s=35

s= 35*3/10

s= 10.5

b=1/3 s = 10.5/3 = 3.5

s= 1/2 p so p= 2s = 2( 10.5) = 21

10.5+3.5 + 21 = 35

4 0
3 years ago
your grades on tests 1 2 and 4 are 82 76 and 90. unfortunately you cut the third test and received a 0. If you have one test lef
Dmitrij [34]

Answer:  No, he can't pass the course.

Explanation:

Since we have given that

Marks on tests 1, 2, and 4 are given by

82, 76, 90 respectively.

Unfortunately, he cut the third test and receive a 0.

According to question, we have given that passing grade for the course is 70, and his one test left to take ,

Let the marks obtained in fifth test be x

So,

\frac{82+76+90+0+x}{5}=70\\\\248+x=5\times 70=350\\\\x=350-248\\\\x=102

And it is not possible to get 102 over 100.

so, he can't still pass the course.

Hence, No, he can't pass the course.

8 0
3 years ago
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