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Yanka [14]
3 years ago
14

Steve travelled from Ashton to Barnfield.

Mathematics
1 answer:
USPshnik [31]3 years ago
5 0

Answer:

67.1

Step-by-step explanation:

Given That:

Time = 200 minutes = 3.5 hours

Distance = 235 miles

We Know That:

Speed = Distance / Time

SO, Speed = 235 divided by 3.5 = 67.1428571

Round this 3sf = 67.1

Hope this helps.

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HELP<br><br> explain what the answer is
Vaselesa [24]

Answer:10/7 and mixed number form is 1 3/7

4 0
2 years ago
Jeremy rides a Ferris wheel. The graph shows h, Jeremy’s height above the ground at any time during the ride. Which inequality r
geniusboy [140]

Answer:

10 \leq h\leq 50

Step-by-step explanation:

Jeremy rides a Ferris wheel. The graph shows h, Jeremy’s height above the ground at any time during the ride

Number line represents the height above the ground at any time during the ride.

the shaded part of the graph lies between 10 and 50, also we have solid dot at 10 and 50.

So height of the inequality is

10 \leq h\leq 50

4 0
3 years ago
Read 2 more answers
Which of the following is a possible situation for the graph shown?
docker41 [41]

Step-by-step explanation:

but the graph is not given here

4 0
2 years ago
Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an
marishachu [46]

Answer: x+x^2+x^3+x^4

Step-by-step explanation:

As per given,

Number of wives = x

Number of sacks = x (\text{Number of wives} )= x\times x = x^2

Number of cats = x(\text{Number of sack})= x \times x^2=x^3

Number of kits = x(\text{Number of cats} )=x\times x^3=x^4

Now , the total number of kits, cats, sacks, and wives going to St. Ives = x+x^2+x^3+x^4

Hence, the required ex[pression:  x+x^2+x^3+x^4

5 0
3 years ago
What is a three digit number thats an odd multiple of three and the product of its digits is 24 and is larger than 15 squared?
Reika [66]
The only way 3 digits can have product 24 is 
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4 
To be divisible by 3 the sum of the digits must be divisible by 3.
1+  3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3. 

So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.

Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.

The others must end in 3. 

They must be greater than 152 which is 225. So the

First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.

The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.  
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
7 0
3 years ago
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