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Juliette [100K]
3 years ago
13

Solve for -2x + 3 < 5.

Mathematics
2 answers:
densk [106]3 years ago
7 0
The answer is x<-1. hope this helps.
VARVARA [1.3K]3 years ago
7 0
Let's solve your inequality step-by-step.
<span><span><span>−2x</span>+3</span><5
</span>Step 1: Subtract 3 from both sides.
<span><span><span><span>−2x</span>+3</span>−3</span><5−3</span><span><span>−2x</span><2
</span>Step 2: Divide both sides by -2.
<span><span><span>−2x/</span>−2</span><<span>2/−2</span></span><span>x>−1
</span>Answer:<span>x>−1</span>
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Answer:


Step-by-step explanation:

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2.Find the Total. Add all the numbers together to get the total. ...

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5 0
3 years ago
5k^3-8-4k^2+5k^2-2+3k^3
lara31 [8.8K]
<h3>I'll teach you how to solve 5k^3-8-4k^2+5k^2-2+3k^3</h3>

-----------------------------------------------------------------------

5k^3-8-4k^2+5k^2-2+3k^3

Group like terms:

5k^3+3k^3-4k^2+5k^2-8-2

Add similar elements:

5k^3+3k^3+k^2-8-2

Add similar elements:

8k^3+k^2-8-2

Subtract the numbers:

8k^3+k^2-10

Your Answer Is 8k^3+k^2-10

Plz mark me as brainliest :)

7 0
3 years ago
Can someone solve 3y − 3 = 2y + 6<br><br> step by step<br> Like the example below
adell [148]
3y - 3 = 2y + 6

-2y -2y

y - 3 = 6

-3 -3


y = 3
4 0
3 years ago
Read 2 more answers
A can in the shape of a cylinder has a diameter of 10 centimeters and a height of 6 centimeters. Which measurement is closest to
Blizzard [7]
I think It’s A! Hope this helps
4 0
3 years ago
Identify the hyperbolas (represented by equations) whose centers are at (2, 1)
weqwewe [10]
When the transverse axis is horizontal, a hyperbola centered at (h,k) has formula (x-h)^2/a^2-(y-k)^2/b^2=1. Plug in h=2, k=1, the formula is (x-2)^2/a^2-(y-1)^2/b^2=1 for some a,b. If the transverse axis is vertical, the formula is (y-h)^2/a^2-(x-k)^2/b^2=1, and (y-2)^2/a^2-(x-1)^2/b^2=1 in our case.
5 0
3 years ago
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