Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
Answer:
Y = 4/5x + 0
Step-by-step explanation:
y - 4 = 4/5(x-5)
y-4=4/5x-4
y=4/5x-4+4
A.
h = 14 ft · sin 30° = 14 ft · 0.5 = 7 ft.
b.
From the bottom of the height to the bottom of the slide:
y² = 14² - 7² = 196 - 49 = 147
y = √147 = 12.12 ft
15 ft - 12.12 ft = 2.88 ft ( from the bottom of the stairs to the bottom of the height )
tan x = 7 / 2.88 = 2.43
∠x = tan^(-1) 2.43
∠x = 67.63° ≈ 68°.
Answer:
Step-by-step explanation:
11×8×k -4= 0
88k. = 4
K. = 1/22
1000x2 = 2000
1000/2 = 500
2000 initial investment
2500 total after all is said and done
equals a $500 total return on the two investments
