The standard form for the equation of a circle is :
<span><span> (x−h)^2</span>+<span>(y−k)^2</span>=r2</span><span> ----------- EQ(1)
</span> where handk are the x and y coordinates of the center of the circle and r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (2,-5)and(8,-9) is :
((2+(8))/2,(-5+(-9))/2)=(5,-7)
So the point (5,-7) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(2−(5))^2+(-5−(-7))^2=9+4=13
⇒r=√13
Subtituting h=5, k=-7 and r=√13 into EQ(1) gives :
(x-5)^2+(y+7)^2=13
Answer:
Help with what is it mental help? Or no cause I’ve dealt with that a lot
Step-by-step explanation:
925 ÷ 8
9 ÷ 8 = 1 r1
put 1 before the 2 = 12
12 ÷ 8 = 1 r 4
4 before 5 = 45
45 ÷ 8 = 5 r 5
So it's 115 r 5
115 and 5/8 refered
Answer:
-16.5 is the amount of distance he jumped and went down
Step-by-step explanation:
Well, you have to ask the question first.
