Factor the denominator:
(3x-1)(x+2)
every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.
since you have factor 3x-1 on top and bottom, in which the zero is 1/3, there would be no solution at x=1/3. it would be a hole.
the answer here is C.
Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
Answer:
16.92
Step-by-step explanation:
5.64 x 3 = 16.92
<em>Hope that helps!</em>
Answer:
x =2
2 in, 6 in, 1 in
Step-by-step explanation:
Answer:
∠NQP = 74°
Step-by-step explanation:
NPQ is a triangle.
We know the sum of 3 angles of a triangle is 180 degrees. So we can write:
N + P + Q = 180
2x + 34 + 2x + 2 = 180
Now, we can solve for x:
The measure of NQP is "2x+2", we plug in x = 36, and find the measure of NQP:
∠NQP = 2(36) + 2 = 74°
