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Step2247 [10]
3 years ago
13

In C++ write a program that prints out PI as a type double and a type float EXACTLY as shown below. Your program should have ONE

cout statement within a loop which alters the width and precision each time through the loop. Do not write 10 separate cout statements for this problem. Show the output in a table that increases the precision from 1 to 10 as shown below. Use dash ('-') as the fill character. Note the differences as the precision gets larger.
Use the following two variables for PI.

double PI_D = 3.14159256359;
float PI_F = 3.14159256359;
Computers and Technology
1 answer:
victus00 [196]3 years ago
3 0

Answer:

#include<iostream>

#include<iomanip>

using namespace std;

int main()

{

double PI_D = 3.14159256359;

float PI_F = 3.14159256359;

cout<<"i"<<"\t\t"<<"Float"<<"\t\t"<<"Double"<<endl;

for(int i = 1; i<=10;i++)

{

 cout<<i<<"-\t\t"<<PI_F<<setprecision(i)<<"-\t\t"<<PI_D<<setprecision(i)<<endl;

}

 return 0;

}

Explanation:

See Attachment where I used comments for explanation

Download cpp
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Explanation:

Your requirements regarding the sum and the negative numbers was a bit vague so I just did something you can probably adjust easily to your liking.

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Find the inverse function of f(x)= 1+squareroot of 1+2x
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Answer:

Therefore the inverse function of  f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

Explanation:

We need to find the inverse of function f(x)=1+\sqrt{1+2x}

Function Inverse definition :

\mathrm{If\:a\:function\:f\left(x\right)\:is\:mapping\:x\:to\:y,\:then\:the\:inverse\:functionof\:f\left(x\right)\:maps\:y\:back\:to\:x.}

y=1+\sqrt{1+2x}\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y

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Simplify

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\mathrm{Square\:both\:sides}

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\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

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\mathrm{Simplify}

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\mathrm{Divide\:both\:sides\:by\:}2

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