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zheka24 [161]
3 years ago
6

Function _one(array)

Computers and Technology
1 answer:
dsp733 years ago
6 0

Answer:

function removeRepeaters(list){

   var goodList = [], badList = {}, used = {}, n;

   // ensure that the argument is indeed an array

   if(!Array.isArray(list)){

        throw "removeRepeaters: Expecting one argument of type Array";

   }

   // loop through the array and take note of any duplicates

   for(n in list) used[list[n]] == true ? badList[list[n]] = true : used[list[n]] = true;

   // now loop through again, and assemble a list of non-duplicates

   for(n in list) if(badList[list[n]] == undefined) goodList[] = list[n];

   return goodList;

}

Explanation:

I assume you're familiar with trinary operators, but just in case, that's what's happening in this first for loop:

for(n in list) used[list[n]] == true ? badList[list[n]] = true : used[list[n]] = true;

this is the same as saying:

for(n in list){

   if(used[list[n]] == true){

       badList[list[n]] = true;

   } else {

       used[list[n]] = true;

   }

}

This loop flags all of the values in the list that are duplicated.  Note that both "badList" and "used" are declared as objects instead of arrays.  This allows us to compare keys in them with an == operator, even if they're not defined, making it a convenient way to flag things.

Note that I haven't tested it, so I may have overlooked something.  I suggest testing it before handing it in.

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PLEASE HELP!! Computer science test
tatiyna

Answer:

See Explanation

Explanation:

Given

The attached function

What the recursion does is that; it adds up individual digits from N to 0

Solving (a): Each output when N = 6

For N = 6.

The function returns the following values:

f(6) = 6

Then: 6 + f(5)

Then: 6 + 5 + f(4)

Then: 6 + 5 + 4 + f(3)

Then: 6 + 5 + 4 + 3 + f(2)

Then: 6 + 5 + 4 + 3 + 2 + f(1)

Then: 6 + 5 + 4 + 3 + 2 + 1 + f(0)

Then: 6 + 5 + 4 + 3 + 2 + 1 + 0 = 21

Solving (b): The output when N = 7

Using the same process in (a) above.

The output is 28

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