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zheka24 [161]
3 years ago
6

Function _one(array)

Computers and Technology
1 answer:
dsp733 years ago
6 0

Answer:

function removeRepeaters(list){

   var goodList = [], badList = {}, used = {}, n;

   // ensure that the argument is indeed an array

   if(!Array.isArray(list)){

        throw "removeRepeaters: Expecting one argument of type Array";

   }

   // loop through the array and take note of any duplicates

   for(n in list) used[list[n]] == true ? badList[list[n]] = true : used[list[n]] = true;

   // now loop through again, and assemble a list of non-duplicates

   for(n in list) if(badList[list[n]] == undefined) goodList[] = list[n];

   return goodList;

}

Explanation:

I assume you're familiar with trinary operators, but just in case, that's what's happening in this first for loop:

for(n in list) used[list[n]] == true ? badList[list[n]] = true : used[list[n]] = true;

this is the same as saying:

for(n in list){

   if(used[list[n]] == true){

       badList[list[n]] = true;

   } else {

       used[list[n]] = true;

   }

}

This loop flags all of the values in the list that are duplicated.  Note that both "badList" and "used" are declared as objects instead of arrays.  This allows us to compare keys in them with an == operator, even if they're not defined, making it a convenient way to flag things.

Note that I haven't tested it, so I may have overlooked something.  I suggest testing it before handing it in.

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4 0
3 years ago
The speed of sound depends on the material the sound is passing through. Below is the approximate speed of sound (in feet per se
german

Answer:

The Java Program for the given problem is as below. Directly copy the code and run it on your machine.

Explanation:

Refer the Screenshots attached for the output.

import java.io.BufferedReader;

import java.io.InputStreamReader;

public class TheSpeedOfSound {

public static void main(String[] s)

{

String medium;

double distance;

double time;

try{

BufferedReader choice = new BufferedReader(new InputStreamReader(System.in));

System.out.println("Enter one of the following: air, water, or steel: ");

medium = choice.readLine(); // reading input i.e. air, water or steel

//check for air water and steel

if (medium.equalsIgnoreCase("air") || medium.equalsIgnoreCase("water") || medium.equalsIgnoreCase("steel")){

System.out.println("Enter the distance the sound wave will travel: ");

distance = Double.parseDouble(choice.readLine()); // read distance value if it is air water or steel

switch (medium)

{

//if medium is air

case "air":

time = distance/1100;

System.out.print("It will take " + time + " seconds.");

break;

//if medium is water

case "water":

time = distance/4900;

System.out.print("It will take " + time + " seconds.");

break;

//if medium is steel

case "steel":

time = distance/16400;

System.out.print("It will take " + time + " seconds.");

break;

}

}

else{

System.out.print("Sorry, you must enter air, water, or steel.");  

}

}

catch(Exception e){

e.printStackTrace();

}

}

}

8 0
3 years ago
Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t
Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

<em>#include<stdio.h></em>

<em />

<em>int main(int argc, char** argv){</em>

<em>    //creating pointer to read a file</em>

<em>    FILE * fp;</em>

<em>    char * line = NULL;</em>

<em>    size_t len = 0;</em>

<em>    ssize_t read;</em>

<em>    int i=0;</em>

<em>    //opening a file</em>

<em>    fp = fopen(argv[1], "r");</em>

<em>    //handling the error condition</em>

<em>    if (fp == NULL){</em>

<em>        printf("File not found..!!");</em>

<em>        return 0;</em>

<em>    }</em>

<em>    int moreThan50 =0;</em>

<em>    //reading a file line by line</em>

<em>    while ((read = getline(&line, &len, fp)) != -1) {</em>

<em>        i = 0;</em>

<em>        if(read >= 50){</em>

<em>            moreThan50++;</em>

<em>        }</em>

<em>        while(i < read){</em>

<em>            if(line[i]!='\n'){</em>

<em>                if(i%50 == 0){</em>

<em>                    printf("\n%c",line[i]);</em>

<em>                }else{</em>

<em>                    printf("%c",line[i]);</em>

<em>                }</em>

<em>            }</em>

<em>            i++;</em>

<em>        }</em>

<em>    }</em>

<em>    printf("\nTotal lines over 50 chars: %d\n",moreThan50);</em>

<em>    printf("Offending Lines: ");</em>

<em>    for(i=1;i<=moreThan50;i++)</em>

<em>        printf("%d, ",i);</em>

<em>    fclose(fp);</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

4 0
2 years ago
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