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finlep [7]
3 years ago
15

Determine the intercepts of the graph described by the following linear equation y=6x+13

Mathematics
1 answer:
Monica [59]3 years ago
4 0
Xintercept is where the line crosses the x axis and where y=0
yintercept is where the line crosses the y axis and where x=0


so
xint is
0=6x+13
minus 13 oth sides
-13=6x
divide by 6
-13/6=x
xint is x=-13/6 or the point (-13/6,0)

yint
set x=0
y=6(0)+13
y=13
yiint is y=13, or the point (0,13)

xint is (-13/6,0)
yint is (0,13)
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Step-by-step explanation:

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8 0
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iVinArrow [24]

❄ Hi there,

let us revise the rounding rules and then, get down to rounding the number.

\sf{Rounding \ Rules:}

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Now we can start the rounding process.

Reading the problem & the directions, we notice that we need to round to 3 decimal places (3 numbers after the decimal point).

Looking at the fourth number, we notice that it's less than 5.

∴ we need to round down ↡

↬\sf{18.57631 \ rounded \ to \ 3 \ DP \ = \bf{18.576}}

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so it would be the first answer

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