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True [87]
4 years ago
6

Factor 64-112w+49w^2

Mathematics
1 answer:
photoshop1234 [79]4 years ago
7 0
49w² -112w + 64
first, you have to find 2 numbers that add up to equal -112, but also multiply together to get a product of 3136 (49 * 64)

two numbers that add to -112 and multiply to equal 3136 is -56 and -56
we can add them into the equation by putting them in for -112x

49w²-56w-56w+64

we now look at what the first 2 numbers have in common and what the last two numbers have in common
49w² and -56w both have w and 7 in common so we can divide 7w
7w(7w -8)
-56w and 64 both have -8 in common so we can divide by -8
-8(7w-8)
now we take the 2 numbers on the outside and bring down the numbers in the brackets

(7w-8)(7w-8)
(7w-8)²

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4 0
3 years ago
Product of 2.8 and 5.1
rewona [7]

Answer:

14.28

Step-by-step explanation:

2.8 times 5.1= 14.28

Hope this helps

-Amelia

3 0
3 years ago
PLSS HELP ASAP. Which of the follow box-and-whisker plots correctly displays this data set?
bonufazy [111]
<h3>Answer:  Choice D</h3>

The five number summary is

  • Min = 23
  • Q1 = 26
  • Median = 28.5
  • Q3 = 30.5
  • Max = 37

===========================================================

Further Explanation:

The original data set is {24, 32, 25, 27, 37, 29, 30, 30, 28, 31, 27, 23}

It sorts to {23, 24, 25, 27, 27, 28, 29, 30, 30, 31, 32, 37} when going from smallest to largest.

There are n = 12 items in this set. The median is found between slots 6 and 7 because n/2 = 12/2 = 6

Circle the items in slot 6 and slot 7 to highlight 28 and 29 in that order. The midpoint is (28+29)/2 = 57/2 = 28.5 which is the median.

Median = 28.5

---------------

Now break the set up into two pieces

L = {23, 24, 25, 27, 27, 28}

U = {29, 30, 30, 31, 32, 37}

L is the lower set below the median, U is the upper set above the median

The midpoint of L is (25+27)/2 = 26 and the midpoint of set U is (30+31)/2 = 30.5

This gives us Q1 = 26 and Q3 = 30.5 respectively

Q1 = first quartile

Q3 = third quartile

The min and max are simply the smallest and largest items of the set

min = 23

max = 37

------------------

We have this five number summary:

  • Min = 23
  • Q1 = 26
  • Median = 28.5
  • Q3 = 30.5
  • Max = 37

These five items directly determine the positioning of the box and whiskers. No extra info is needed.

The min and max handle the tips of the left and right whiskers if we don't have any outliers. In this case, we don't have outliers so we can ignore this aspect.

The Q1 and Q3 handle the left and right edges of the box

The median (aka Q2) is the vertical line inside the box. It doesn't have to be at the center of the box. It's simply anywhere inside.

With all this in mind, the best match is <u>choice D</u>

  • The tip of the left whisker is at 23
  • The left edge of the box is at 26
  • The vertical line inside the box is at 28.5
  • The right edge of the box is at 30.5
  • The tip of the right whisker is at 37

----------------------------------

In other words, we can eliminate the following

  • A) Because the right edge of the box for choice A is at 31 when it should be at 30.5
  • B) The tip of the right whisker is at 35 when it should be at 37
  • C) The tip of the left whisker is at 21 when it should be at 23

Since A, B, and C are eliminated, the only thing left is <u>choice D</u> which matches all aspects of the five number summary above.

8 0
2 years ago
Solve the following equation. Show all your work.
horrorfan [7]
\dfrac{x}{x - 2} + \dfrac{x - 1}{x + 1} = -1

(x - 2)(x + 1) \times \dfrac{x}{x - 2} + (x - 2)(x + 1) \times \dfrac{x - 1}{x + 1} = -1(x - 2)(x + 1)

(x + 1)x + (x - 2)(x - 1) = -1(x - 2)(x + 1)

x^2 + x + x^2 - 3x + 2 = -x^2 + x + 2

3x^2 - 3x = 0

3x(x - 1) = 0

x = 0~~~or~~~x - 1 = 0

x = 0 ~~~ or ~~~ x = 1


Since neither 0 nor 1 cause a zero in a denominator in the original equation, 0 and 1 are acceptable as solutions.

Answer: x = 0 or x = 1



8 0
3 years ago
Whats times what equals negative 48 and adds up to negative 2
Georgia [21]
6 × -8 = -48

6 + -8 = -2
6 0
4 years ago
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