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Sindrei [870]
3 years ago
7

John bikes 22 km per hour and starts at mile 10. Gymn bikes 28 km per hour and starts at mile 0. Which system of linear equation

s represents this situation?
Mathematics
1 answer:
leonid [27]3 years ago
7 0

Answer:

Step-by-step explanation:

The following are linear equations for the distance that John has biked (J) and the distance that Gymn has biked (G). These two equations represent the situation being described using the values provided.

J = 22x + 10

G = 28x + 0

In these equations the variable x represents the number of hours each of the bicyclists have biked.

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The correct option is :   no mode

<u><em>Explanation</em></u>

The given data set is:  9, 15, 86, 13, 16, 101, 85, 10, 14, 17, 102

The <u>mode is the number that is repeated more often</u> than any other number in the data set.

But here we can see that all the numbers in this data set are different. That means <u>they appear only once</u>.

So, there will be 'no mode' in this set.

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Base of a triangle is 15 height is 7 what is area of triangle
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Answer:

b·h=105

Step-by-step explanation:

u multiply the base times the height

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How many milliliter of pure acid should be added to 10 ml of 20% acid to make 50% acid solution? Round answer to the nearest hun
Ymorist [56]
We have 10 ml of 20% acid to which we need to add "x" milliliters of 100% acid to make 50% acid.
 
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Source:
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Scroll down to problem B


5 0
3 years ago
A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st
ss7ja [257]

Answer:

Step-by-step explanation:

Hello!

The researcher wants to test if the valve plates manufactured have the expected tensile strength of 5 lbs/mm. So he took a sample of 42 valve plates and measured their tensile strength, obtaining a sample mean of X[bar]= 5.0611 lbs/mm and a sample standard deviation of S=0.2803 lbs/mm.

The study variable is:

X: tensile strength of a valve plate (lbs/mm)

The parameter of interest is the mean tensile strength of the valve plates, μ.

If the claim is that the valve plates of the sample have on average tensile strength of 5 lbs/mm, symbolically: μ = 5

a) The statistic hypotheses are:

H₀: μ = 5

H₁: μ ≠ 5

b) To determine the critical values and rejection region of a hypothesis test you need three to determine three factors of the hypothesis test:

1) The statistical hypothesis.

2) The significance level.

3) The statistic to use for the analysis.

The statistic hypothesis determines the number of critical values and the direction of the rejection region, in this case, the test is two-tailed you will have two critical values and the rejection region will be divided into two.

With the statistic, you will determine the distribution under which you will work and the significance level determines the probability of rejecting the null hypothesis.

To study the population mean you need that the variable of interest has at least a normal distribution, there is no information about the distribution of the study variable but the sample size is large enough n≥30, so you can apply the central limit theorem to approximate the distribution of the sample mean to normal: X[bar]≈N(μ;σ²/n)

Thanks to this approximation it is valid to use an approximation of the standard normal distribution for the test:

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } }≈N(0;1)

The critical values are:

Z_{\alpha /2}= Z_{0.05}= -1.648

Z_{1-\alpha /2}= Z_{0.95}= 1.648

You will reject the null hypothesis if Z_{H_0}≤-1.648 or if Z_{H_0}≥1.648

You will not reject the null hypothesis if -1.648<Z_{H_0}<1.648

c)

Z_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }=  \frac{5.0611-5}{\frac{0.2803}{\sqrt{42} } }= 1.41

d) The value of the statistic is between the two critical values so the decision is to not reject the null hypothesis. Then using a significance level of 10% there is no significant evidence to reject the null hypothesis so the valve plates have on average tensile strength of 5 lbs/mm.

e) The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis). If the test is two-tailed, so is the p-value, you can calculate it as:

P(Z≤-1.41) + P(Z≥1.41)= P(Z≤-1.41) + (1 - P(Z≤1.41))= 0.079 + ( 1 - 0.921)= 0.158

p-value: 0.158

I hope it helps!

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