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Pani-rosa [81]
2 years ago
14

382 3/10 - 191 87/100=

Mathematics
2 answers:
jonny [76]2 years ago
8 0
382\frac{3}{10}-191\frac{87}{100}=\ \ \ | make\ a\ common\ denominator\\\\
382\frac{30}{100}-191\frac{87}{100}=\\\\
381\frac{130}{100}-191\frac{87}{100}=190\frac{130-87}{100}=190\frac{43}{100}\\\\Solution\ is\ 190,43.
xenn [34]2 years ago
8 0
First you need to find a common denominator , which is 100 . so multiply 3/10 by 10 with both the numerator and denominator. So your new equation should be 382 30/100 - 191 87/100. Even though 382 is larger than 191 , 3/100 is still less than 87/100. So what i do is cross out the first/whole number and then add the denominator. so i change it to look like this....

381 130/100 - 191 87/100

this way its still the same fraction but it will be easier to subtract

so first subtract 381 and 191 which equals 190
then subtract the fractions 130/100 - 87/100 which equals 47/100

so your final answer is 190 47/100
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\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

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Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

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{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

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