All categories

3 years ago

Find 41% of 48. Round to the nearest tenth of necessary

Mathematics

1 answer:

pshichka [43]3 years ago

8 0

Answer:

19.7

Step-by-step explanation:

1. Change the percent to a decimal

0.41 of 48

2.Multiply the two numbers together.

0.41 of 48 = 19.68

3. Round to nearest tenth

19.68 = 19.70 = 19.7

You might be interested in

Please help due pretty soon

docker41 [41]

Answer:

Step-by-step explanation:

just trust me I know what I'm talking about

5 0

3 years ago

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

Read the above and answer

svetlana [45]

Answer:

Linear Pair:

∠ 1 and ∠ 2

Vertical Angles:

∠ 1 and ∠ 3

Supplementary Angles:

∠ 7 and ∠ 6

Step-by-step explanation:

Linear Pair:

A linear pair of angles is formed when two lines intersect.

Two angles are said to be linear if they are adjacent angles formed by two intersecting lines.

The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

Example

∠ 1 and ∠ 2 ∠ 8 and ∠ 5 ,etc

Vertical Angles:

The angles opposite each other when two lines cross.

They are always equal.

Example

∠ 1 and ∠ 3 ∠ 8 and ∠ 6 ,etc

Supplementary Angles:

Two Angles are Supplementary when they add up to 180 degrees.

Examples two angles (140° and 40°)

All Linear pair are Supplementary angles

Example

∠ 7 and ∠ 6 ∠ 8 and ∠ 5 ,etc

3 0

3 years ago

Not sure how to go at this at all, please help.

ss7ja [257]

Here ya go answer down below

8 0

2 years ago

Read 2 more answers

Find the volume of the cylinder. Use 3.14 for Pi. Round your answer to the nearest hundredth.the height is 13 and the radius is

NikAS [45]

Answer:

The volume of the cylinder is 2002 square units.

Step-by-step explanation:

It is given that,

Height of the cylinder, h = 13 units

Radius of the cylinder, r = 7 units

We need to find the volume of the cylinder. The formula of the volume of cylinder is given by :

$V=\pi r^2 h\\\\V=\dfrac{22}{7}\times 7^2 \times 13\\\\V=2002\ \text{unit}^2$

So, the volume of the cylinder is 2002 square units.

4 0

3 years ago