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Komok [63]
3 years ago
6

Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse B A is 9.8 inches, the length of C B is 6.3 inch

es, and the length of C A is 7.5 inches.
Which expressions can be used to find m∠ABC? Select two options.


cos−1(StartFraction 9.8 Over 6.3 EndFraction)

cos−1StartFraction 6.3 Over 9.8 EndFraction)

cos−1(StartFraction 7.5 Over 9.8 EndFraction)

sin−1(StartFraction 9.8 Over 7.5 EndFraction)

sin−1(StartFraction 7.5 Over 9.8 EndFraction)

Mathematics
2 answers:
german3 years ago
7 0

Answer:

\angle B=\cos^{-1}\left(\dfrac{6.3}{9.8}\right)\\ \\\angle B=\sin^{-1}\left(\dfrac{7.5}{9.8}\right)

Step-by-step explanation:

Consider right triangle ABC with right angle C.

In this triangle,

  • BA = 9.8 in
  • CB = 6.3 in
  • CA = 7.5 in

Write trigonometric functions:

\cos \angle B=\dfrac{BC}{AB}=\dfrac{6.3}{9.8}\\ \\\sin \angle B=\dfrac{AC}{AB}=\dfrac{7.5}{9.8}

Hence,

\angle B=\cos^{-1}\left(\dfrac{6.3}{9.8}\right)\\ \\\angle B=\sin^{-1}\left(\dfrac{7.5}{9.8}\right)

Bogdan [553]3 years ago
4 0

Answer:

C

Step-by-step explanation:

JUST TOOK THE TEST ON EDG

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ivolga24 [154]

\huge\mathbf{Answer࿐}

\underline{ \underline{ \bf{step} - 1}}

Taking first equation,

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\underline{ \underline{ \bf{step} - 2}}

plugging the value of y in second equation,

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\underline{ \underline{ \bf{step} -3}}

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