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sveta [45]
3 years ago
9

If 6 friends shared 1/3 of a pan of brownies, how much of the pan does each friend get?

Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0

Since she shared 1/3of brownies with 6 friends it would be 6/ 1/3= 6/1 •1/3 so each friend got 6/3 of the pan

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Please Help Me!
Rainbow [258]
For the first option, the range is a measure of variability which measures the spread of the data set from the least value to the greatest value, but it does not take into account the variability of the other data values of the data set. The range is easily affected by the presence of outliers (data points that are away from other data points). Thus the range is regarded as a weak measure of variability and is not used when other measures of variability are available. Thus, that the range of the two data sets are equal does not mean that the data sets have the same variability. Therefore, the first option is not the correct answer.

For the second option, the median is not a measure of variability. Thus, that a data set has a greater median than another data set does not mean that the data set would have a greater variability. Therefore, the second option is not the correct answer.
For the third option, the inter-quartile range (IQR) is a better measure of variability than the range because it takes into account more data points than the range. Now, because, the the IQR of Team 2 is less than the IQR of Team 1, this shows that Team 1 have greater variability than Team 2 and thus the conclusion of the coaches are inaccurate. Therefore, the third option is the correct answer.

For the fourth option, the mean absolute deviation, MAD, is a better measure of variability than the IQR because it takes into account all the points of the data set. While IQR measures variability with respect to the median, MAD measures variability with respect to the mean. Because we are told that the data sets are not symmetrical, the median will be a better measure of the center than the mean, thus the IQR will present a better measure of the variability of the data sets. Thus, though the MAD for Team 2 was calculated to be a larger number than the MAD for Team 1, the information can be misleading in arriving at a conclusion on which data set has more variability because the data sets are not symmetrical. Therefore, the fourth option is not the correct answer.
4 0
3 years ago
Read 2 more answers
What is the correct reason for statement 1
olya-2409 [2.1K]

Answer:

Given

Step-by-step explanation:

You are given the information about the angles under the line given.

6 0
3 years ago
Find the numerical value of the log expression. \log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3 loga=7logb=10logc=3 \log \
bija089 [108]

Answer:

  32

Step-by-step explanation:

  \log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3\\\\ \log \dfrac{a^8c^2}{b^3}=8\log{a}+2\log{c}-3\log{b}=(8)(7)+(2)(3)-(3)(10)\\\\=56+6-30=\boxed{32}

__

The applicable rules of logarithms are ...

  log(ab/c) = log(a) +log(b) -log(c)

  log(a^b) = b·log(a)

6 0
3 years ago
a bag contains 10 white gold balls and 6 striped golf balls. a golfer wants to add 112 golf balls to the bag. he wants the ratio
wolverine [178]

Answer:70 white golf balls and 42 striped golf balls

Step-by-step explanation:

First we find the ratio of white to striped balls

White golf balls = 10

Striped golf balls = 6

Ratio = 10/6 = 5/3

We are told a golfer wants to add extra 112 balls to the already 16 balls

And the ratio after adding 112 balls must stay the same

First we label the extra golf balls to be added x and y

x = white golf balls

y = striped golf balls

So since we know the 112 balls added is a combination of the extra white golf balls and striped golf balls, we create an equation for that, labelling it (1)

x + y = 112 (1)

And we are told that after putting these extra balls the ratio must remain the same, which is 5/3

which will be (10 white balls + x) divided by (6 striped ball + y) will be equals to 5/3

So we create another equation for this, labelling it (2)

(10+x)/(6+y) = 5/3 (2)

So we have two simultaneous equations

We pick (1)

x + y = 112

We either make x or y the subject of formula, I choose to make x the subject of formula, we label the equation (3)

take y to the other side, causing it to change to -y

x = 112 - y (3)

We then work with (2)

(10+x)/(6+y) = 5/3

We cross multiply

3(10+x) = 5(6+y)

We open the brackets

Making the equation simplified and labelling it (4)

30 +3x = 30 + 5y

Collect like terms

3x -5y = 30-30

3x -5y = 0 (4)

Remember from (3) we know that

x = 112 -y

So we put (3) in (4)

3(112 - y) - 5y = 0

Open bracket

336 -3y -5y =0

336 -8y = 0

Transfer -8y to the other side, changing to +8y

336 = 8y

Divide both sides by 8

336/8 = y

42 = y

y = 42

from (3) we know that x equals 112 - y

So we put y = 42 in (3)

x = 112 - y

x = 112 -42 = 70

x = 70

So therefore number of white golfs balls and striped golfs balls to be added to keep the same ratio is 70 and 42 respectively

4 0
3 years ago
How many real solutions does this system of equations have? xy = 9<br> y = 3x - 1
tekilochka [14]

Answer:

two real, unequal roots

Step-by-step explanation:

y is definied as y = 3x - 1.  Substitute 3x - 1 for y in xy = 9, obtaining:

x(3x - 1) = 9.  Then:

3x^2 - x - 9 = 0.  In this quadratic, the coefficients are a = 3, b = -1 and c = -9.

Calculating the discriminant b^2 - 4ac, we get (-1)^2 - 4(3)(-9), or 1 + 108, or 109.  Because the discriminant is positive, we have two real, unequal roots.

6 0
3 years ago
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