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9966 [12]
4 years ago
8

Which method would be the BEST to protect security information and event management (SIEM) log data at rest from tampering by au

thorized users?A. Access control lists (ACLs) on log data drivesB. Deployment of write once read many (WORM) drivesC. Disk encryption using hardware security modules (HSM) on log data drivesD. Implementing the principle of least privilege on log data drives
Computers and Technology
1 answer:
AnnyKZ [126]4 years ago
7 0

Answer:

Option B (Deployment of write once read many (WORM) drives) is the appropriate one.

Explanation:

  • SIEM application goods/services consolidate safety information management (SIM) with security event management (SEM) throughout the area of device protection. We include an overview including its known vulnerabilities created by users and network equipment in actual environments.
  • No quantity of administrative intervention will alter the substance on something like a WORM disc, even by physical disc disruption or failure. That would be the better-suggested choice.
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alexira [117]

Answer:

A) 2.56 ms

B) 128 μs

Explanation:

Time for Bus cycles = 500 ns

Transfer of bus control = 250 ns

I/0 device data transfer rate = 50 KB/s

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A) Determine how long the device tie up the bus when transferring a block of 128 bytes

Block size to be transferred = 128 bytes

Bandwidth = 50 KB/s

data transfer = (Block size ) / ( Bandwidth)

                     = ( 128 * 8 ) / ( 50 * 10^3 * 8 )

                     = ( 1024 ) / ( 50 * 10^3 * 8 )

                     = 2.56 ms

To determine the actual transfer time  we have to add up the transfer time for the bus control in both directions :

2.56 ms + 500 ns = 2.56 ms. this is because 500 ns is not a significant value

B) cycle stealing mode

In this mode each byte is transferred at a time and The total transfer time needed for the bus control in both directions will be double the total time i.e 2 * 500 ns = 1000 ns. because additional control time of  250 ns is required at both ends

since 1 byte is transferred at a time , 1 byte will be transferred in 1 μs

128 bytes = 128 *  1 μs = 128 μs

4 0
3 years ago
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notka56 [123]

Answer:

The answer is "compromise"

Explanation:

In computer science, the comprised system is used to describe as any technological resource, that has been negatively affected by an untrustworthy source for nondisclosure, integrity or accessibility either deliberately or inadvertently.

  • In this, the mechanical interaction from the unauthorized source or technological progress can result in compromise.
  • This helps you and the partner to meet each other's interests by taking into consideration both the positions and the solution to the main problem.

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Explanation:

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