<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
We need to get rid of expression parentheses.
If there is a negative sign in front of it,
each term within the expression changes sign.
Otherwise, the expression remains unchanged.
Numerical 'like' terms will be added. There is only one group of like terms
the answer is: ab-4a-5
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Answer:
30.11 meters ( approx )
Step-by-step explanation:
Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )
Given,
Point A is 8.20 m above level ground,
So, the height of the building = ( x + 8.20 ) meters,
Now, 1 degree = 60 minutes,
⇒ 


By the below diagram,




Now, again by the below diagram,



Hence, the height of the building = x + 8.20 = 30.11 meters (approx)