$\dfrac{2+6i}{2-4i}\\\\\\=\dfrac{2(1+3i)}{2(1-2i)}\\\\\\=\dfrac{1+3i}{1-2i}\\\\\\=\dfrac{(1+3i)(1+2i)}{(1-2i)(1+2i)}\\\\\\=\dfrac{1+2i+3i+6i^2}{1-(2i)^2}\\\\\\=\dfrac{1+5i-6}{1+4}~~~~;[i^2=-1]\\\\\\=\dfrac{5i-5}{5}\\\\\\=\dfrac{5(i-1)}5\\\\=i-1\\\\=-1+i\\\\\text{It is in a form of a +bi so,}~ a = -1~ \text{and}~ b = 1$

6 0

2 years ago

R --> 2 P. Initially you start off with 0.5 M reactants and let the reaction run to equilibrium and calculate the equilibrium

Anit [1.1K]

Answer:

K still the same value

Step-by-step explanation:

given a reaction aA+bB<->cC+dD the constant K is defined as:

$\frac{C^{c}D^{d} }{A^{a}B^{b} }$

K is a constant so it won't change the value. Instead, the values of C and D are going to change. The position of equilibrium moves because of the need to keep a constant value for the equilibrium constant.

8 0

2 years ago

HELP !! PLS SOMEONE :((

GaryK [48]

Answer:

A (2,-2.5)

Step-by-step explanation:

Is 2 units right and 2.5 units down, right where point C is.

8 0

2 years ago

Need some great assistance! Thanks!

Lostsunrise [7]

Answer:

Step-by-step explanation:

step by step explanation I'm probly wrong

7 0

3 years ago