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murzikaleks [220]
3 years ago
13

Consider the function shown.

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0
The function is decreasing from x=1 to x=8. See the attachment.

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62,000 is 1/10th of​
djyliett [7]

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Should be 620,000

Step-by-step explanation:

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Covert 5 kilograms into grams
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5000 grams .....................

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Triangles Unit Test part 1 A length of rope is stretched between the top edge of a building and a stake in the ground. The head
musickatia [10]

Answer:

The building is 32 feet tall.

Step-by-step explanation:

Consider the figure drawn below representing the given scenario.

AB represents the height of building, BC is the distance between the stake and building, C represents the stake at ground level, and DE represents the height of the tree growing halfway between building and stake.

Since the tree is growing halfway between B and C, therefore, the point E divides the line segment BC into 2 equal parts.

Therefore, BE = EC or E is the midpoint of BC.

Also, from the figure, it is clear that both tree and building are vertical to the ground. So, DE || AB.

Now, from converse of mid-segment theorem, if a line passes through the midpoint of one side of a triangle and also parallel to the third side, then the line also passes through the midpoint of the second side and half the length of the third side (parallel side)

So,

DE=\frac{1}{2}\times AB\\\\16=\frac{AB}{2}\\\\AB=16\times 2=32\ ft

Therefore, the building is 32 feet tall.

5 0
3 years ago
6/5<br><br> 36/25<br> Find the 10th term.
harina [27]

Answer:

36/25=1 and 11/25  6/5=1 and 1/5

Step-by-step explanation:

booooooooooooooo

5 0
2 years ago
a scuba diver descended at a rate of 2 1/4 per second. If 0 represents the surface of the water and distances below the surface
Shtirlitz [24]

Answer:

The location will be at - 28\frac{1}{8} units.

Step-by-step explanation:

A scuba diver descended at a rate of 2\frac{1}{4} units per second.

Now, if 0 represents the surface of the water and distances below the surface are negative, then after 12\frac{1}{2} seconds the location of the diver will be given by the followings :

In one second the diver descends by 2.25 units depth.

So, in 12.5 seconds the diver will descend by (2.25 \times 12.5) = 28.125 units i.e. 28\frac{1}{8} units depth.

Therefore, the location will be at - 28\frac{1}{8} units. (Answer)

6 0
3 years ago
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