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Lisa [10]
3 years ago
10

Rewrite this formula to convert Fahrenheit to Celsius (linear equations and inequalities)

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0

Answer:

The formula used to convert   Fahrenheit in to Celsius is:

C = ( F - 32) \times (\frac{5}{9})

Step-by-step explanation:

Here, the given expression is :

F=(\frac{9}{5}) c + 32

The above  expression converts Celsius in to Fahrenheit.

Now we need an expression to convert   Fahrenheit in to Celsius.

Simplifying the above  for the value of C, we get:

F=(\frac{9}{5}) c + 32\\\implies F - 32 =(\frac{9}{5}) c \\\implies  ( F - 32) \times (\frac{5}{9})   = c\\\implies C = ( F - 32) \times (\frac{5}{9})

Hence, the formula used to convert   Fahrenheit in to Celsius is:

C = ( F - 32) \times (\frac{5}{9})

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slavikrds [6]
Since A (area of circle = C) is given = 148
Where we assume:
Y represents radius of the circle (r)
X represents diameter of the circle (D)
Pi (π) = 3.14
A = 2 * π * y
148 = 2 * 3.14 * y
148 = 6.28 * y
y = 148/6.28
So, y = 23.56

D = 2 * y
D = 2 * 23.56
So, D = 47.12

Assume A is unknown (not given as 148)
A = π * y^2
A = 3.14 * (23.56)^2
A = 3.14 * 47.12
So, A = 147.95 (approx. A = 148)
3 0
3 years ago
the lengths of the sides of a triangle are in the ratio of 5:3:4. The perimeter of the triangle is 156cm. Find the length of the
lisabon 2012 [21]
The longest side is 5/(5+3+4) = 5/12 of the perimeter, hence
  (5/12)*156 cm = 65 cm . . . . . the length of the longest side
4 0
3 years ago
Multiply. x^2 + 8x + 15/x-4 x x^2-16/2x+6
Sophie [7]
= 1/2 ( x + 5 ) ( x + 4 )
5 0
4 years ago
Read 2 more answers
Let f and g be the functions defined by f(x) = 10^ (x+2 / 3) and g(x) = log (x3 / 100) for all positive real numbers,
Vaselesa [24]

Answer:

F(x) and g(x) are not inverse functions.

Step-by-step explanation:

In order to calculate the inverse function of a function, we have to isolate X and after that, we change the variables.

As our function f(x) is a exponentian function, we can apply logarithm with base 10 (log) in both sides in order to isolate X. Remember that log10=1.

[tex]y=10^{(x+\frac{2}{3}) }\\\\log y=log 10^{(x+\frac{2}{3}) }\\log y = (x+\frac{2}{3}) . log10\\\frac{log Y}{log10} = (x+\frac{2}{3})\\\frac{log Y}{1} = (x+\frac{2}{3})\\log Y-\frac{2}{3}=x[/tex]

Now we change the variables.

F(x)=log x-\frac{2}{3}

F(x) and g(x) are not inverse functions.

4 0
3 years ago
CON PROCESOS POR FAVOR
labwork [276]

Answer:

\dfrac{149}{40}

\dfrac{38}{15}

Step-by-step explanation:

(\dfrac{7}{8} + \dfrac{4}{5}) - (\dfrac{9}{20} + \dfrac{-5}{2}) =

= (\dfrac{7}{8} \times \dfrac{5}{5} + \dfrac{4}{5} \times \dfrac{8}{8}) - (\dfrac{9}{20} + \dfrac{-5}{2} \times \dfrac{10}{10})

= (\dfrac{35}{40} + \dfrac{32}{40}) - (\dfrac{9}{20} + \dfrac{-50}{20})

= \dfrac{67}{40} - (-\dfrac{41}{20})

= \dfrac{67}{40} + \dfrac{41}{20} \times \dfrac{2}{2}

= \dfrac{67}{40} + \dfrac{82}{40}

= \dfrac{149}{40}

(-\dfrac{6}{4} + \dfrac{3}{2}) + (\dfrac{6}{5} + \dfrac{4}{3}) =

= (-\dfrac{3}{2} + \dfrac{3}{2})+ (\dfrac{6}{5} \times \dfrac{3}{3} + \dfrac{4}{3} \times \dfrac{5}{5})

= 0 + \dfrac{18}{15} + \dfrac{20}{15}

= \dfrac{38}{15}

4 0
2 years ago
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