Answer:
Let's choose the three odd consecutive numbers 1, 3, and 5.
3^2=9
1•5=5
9-5=4
Let's try the same thing, but with the numbers 101, 103, and 105.
103^2=10609
101•105=10605
10609-10605=4
So, yes, the square of the second number out of three consecutive odd numbers is four greater than the product of the first and the third numbers.
The answer is 2990.8 yd
Formula for SA of cylinder: 2*pi*r*h+2*pi*r^2
Formula for radius: diameter/2
Plug the radius, 17, height, 11, and pi, 3.14, into the formula above.
= 2990.8 yd
⇒If parallelogram A B CD is a rectangle, then Diagonals of parallelogram that is of rectangle will be of equal Length.
That is , Diagonal AC = Diagonal B D
⇒Given, AX= 3 y- 5
So, AC= 2 × (3 y- 5)→→[Diagonals of Parallelogram Bisect each other]
And, B D = 5 y
So,A C = B D ⇒→→Diagonals of a rectangle are equal.]
→2 ×(3 y - 5) = 5 y
→ 6 y - 10 = 5 y →→[Using Distributive Property of subtraction with respect to multiplication]
Combining Like terms that is Variables with Variables and Constant with Constant.
→ 6 y - 5 y = 10
→ y = 10
Answer:
The Answer would be No
Step-by-step explanation:
Hope im correct.
I did this when i was in middle school
Answer:
a. 100.48
b. 1,004.8
c. 1,105.28
Step-by-step explanation:
a. a cone with volume = ⅓×3.14×4²×6=
100.48
b. a cylinder with volume = 3.14×4²×20=
1,004.8
c. total volume = 100.48+1,004.8
= 1,105.28
