Evaluate the expression w^2 - v + 1 for w = -2 and v = -8. -3 -11 13 5

Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool. If it takes 30 minutes for the la

Anuta_ua [19.1K]

Answer:

60 minutes for the larger hose to fill the swimming pool by itself

Step-by-step explanation:

It is given that,

Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.

takes 30 minutes for the larger hose to fill the swimming pool by itself

Let x be the efficiency to fill the swimming pool by larger hose

and y be the efficiency to fill the swimming pool by larger hose

To find LCM of 20 and 30

LCM (20, 30) = 60

To find the efficiency

Let x be the efficiency to fill the swimming pool by larger hose

and y be the efficiency to fill the swimming pool by larger hose

x = 60/30 =2

x + y = 60 /20 = 3

Therefore efficiency of y = (x + y) - x =3 - 2 = 1

so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes

8 0

3 years ago

Which equation is the inverse of y = 16x2 + 1?

Llana [10]

Answer:

$y=\frac{\sqrt{x-1} }{4}$

Step-by-step explanation:

The given equation is

$y=16x^2+1$

For this function to have an inverse, we must restrict the domain, say $x\ge0$

We interchange x and y to get,

$x=16y^2+1$

We now make y the subject to get;

$x-1=16y^2$

We divide through by 16 to get;

$\frac{x-1}{16}=y^2$

We now take the square root of both sides to get;

$\pm \sqrt{\frac{x-1}{16}}=y$

$y=\pm \frac{\sqrt{x-1} }{4}$

Since $x\ge 0$ , the inverse function is

$y=\frac{\sqrt{x-1} }{4}$

6 0

3 years ago

Edwin has $2,325.35 he divided put 2/5 into his bank account how much does he have left for his checking account

alexandr402 [8]

$Find \ \frac{1}{5} \ of \ \$2,325.35
\\\ 2325.35/5 = 465.07
\\\ 465.07*2 = 930.14
\\\ 2325.35- 930.14 = 1395.21
\\\ \boxed{1395.21}$

7 0

3 years ago

PLEASE PLEASE PLEASE HELP I NEED HELP WITH THIS :(( i will give brainliest:)

bezimeni [28]

-3+8=5

2-6=-4

-3+-1=-4

4 0

3 years ago

cho tứ giác ABCD. Gọi M,N,P,Q là trung điểm của các cạnh AB, CD, AD, BC. Chứng minh rằng vecto MP = vecto QN, vecto MQ = vecto P

Dmitriy789 [7]

Answer:

Step-by-step explanation:

Xét tam giác DAB có: P là trung điểm AD, M là trung điểm AB

=> MP là đường trung bình của tam giác DAB => MP//BD và MP= $\frac{1}{2}$ BD (1)

Xét tam giác DBC có: N là trung điểm DC, Q là trung điểm BC

=> QN là đường trung bình của tam giác DBC => QN//BD và QN= $\frac{1}{2}$ BD (2)

Từ (1) và (2) => vecto MP song song cùng chiều với vecto QN

và độ dài MP = độ dài QN = $\frac{1}{2}$ BD

=> vecto MP = vecto QN

Tương tự xét các tam giác DAC và tam giác ABC => vecto MQ = vecto PN

4 0

2 years ago