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4 years ago

What is the exponential expression for the numerical expression 5⋅5⋅5⋅5 ?

Mathematics

1 answer:

skelet666 [1.2K]4 years ago

8 0

Answer:

$5^{4}$

Step-by-step explanation:

Note the number 5 is repeated 4 times, hence we can say that the expression 5⋅5⋅5⋅5 is equivalent to 5 raised to the power of 4 or $5^{4}$

edit : correct spelling

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ANSWER CORRECTLY AND IF YOU DONT KNOW IT JUST DONT SAY ANYTHING

arlik [135]

9514 1404 393

Answer:

A. 40, dollars added per day to the bank account

B. y -600 = 40(x -0); y = 40x +600; 40x -y = -600

C. f(x) = 40x +600

D. $880

Step-by-step explanation:

A. The slope is given by the formula ...

m = (y2 -y1)/(x2 -x1)

m = (720 -600)/(3 -0) = 120/3

m = 40

The bank account is increasing at the rate of $40 per day.

B. Point-slope form is ...

y -k = m(x -h) . . . . . line with slope m through point (h, k)

Using the first point, we have (h, k) = (0, 600) and m = 40.

y -600 = 40(x -0)

Slope-intercept form is ...

y = mx +b . . . . . . line with slope m and y-intercept b

The first point tells us the y-intercept is b=600, so the equation is ...

y = 40x +600

Standard form is ...

ax + by = c . . . . . . . a > 0, and a, b, c mutually prime

This form can be obtained by subtracting y from the point-slope form.

40x -y = -600

C. Replacing y with f(x) in the slope-intercept form gets the desired equation.

f(x) = 40x +600

D. The table shows the balance after 6 days. The balance increases $40 each day, so the balance after 7 days is ...

$840 +40 = $880 . . . . balance after 7 days

5 0

3 years ago

Cathie is making a dress with a sash. The sash needs to be 72.8 inches long, but Cathie's measuring tape is only in centimeters.

r-ruslan [8.4K]

<span>The sash needs to be 184.912 cm. to equal 72.8 in.</span>

4 0

3 years ago

Use a triple integral to find the volume of the tetrahedron T bounded by the planes x+2y+z=2, x=2y, x=0 and z=0

Tanzania [10]

Answer:

Volume of the Tetrahedron T = $\frac{1}{3}$

Step-by-step explanation:

As given, The tetrahedron T is bounded by the planes x + 2y + z = 2, x = 2y, x = 0, and z = 0

We have,

z = 0 and x + 2y + z = 2

⇒ z = 2 - x - 2y

∴ The limits of z are :

0 ≤ z ≤ 2 - x - 2y

Now, in the xy- plane , the equations becomes

x + 2y = 2 , x = 2y , x = 0 ( As in xy- plane , z = 0)

Firstly , we find the intersection between the lines x = 2y and x + 2y = 2

∴ we get

2y + 2y = 2

⇒4y = 2

⇒y = $\frac{2}{4} = \frac{1}{2}$ = 0.5

⇒x = 2( $\frac{1}{2}$ ) = 1

So, the intersection point is ( 1, 0.5)

As we have x = 0 and x = 1

∴ The limits of x are :

0 ≤ x ≤ 1

Also,

x = 2y

⇒y = $\frac{x}{2}$

and x + 2y = 2

⇒2y = 2 - x

⇒y = 1 - $\frac{x}{2}$

∴ The limits of y are :

$\frac{x}{2}$ ≤ y ≤ 1 - $\frac{x}{2}$

So, we get

Volume = $\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}\int\limits^{2-x-2y}_{z=0} {dz} \, dy \, dx$

= $\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{[z]}\limits^{2-x-2y}_0 {} \, \, dy \, dx$

= $\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{(2-x-2y)} \, \, dy \, dx$

= $\int\limits^1_0 {[2y-xy-y^{2} ]}\limits^{1-\frac{x}{2}} _{\frac{x}{2} } {} \, \, dx$

= $\int\limits^1_0 {[2(1-\frac{x}{2} - \frac{x}{2}) -x(1-\frac{x}{2} - \frac{x}{2}) -(1-\frac{x}{2}) ^{2} + (\frac{x}{2} )^{2} ] {} \, \, dx$

= $\int\limits^1_0 {(1 - 2x + x^{2} )} \, \, dx$

= ${(x - x^{2} + \frac{x^{3}}{3} )}\limits^1_0$

= 1 - 1² + $\frac{1^{3} }{3}$ - 0 + 0 - 0

= 1 - 1 + $\frac{1 }{3}$ = $\frac{1}{3}$

So, we get

Volume = $\frac{1}{3}$

7 0

3 years ago

Extra Credits:

Effectus [21]

Answer:

Missing Number) 55

Property being used) Distributive

Step-by-step explanation:

To find the missing number, just plug in reasonable numbers from the other equation. It is distributive because the 55 is being distributed into everything that is inside the parentheses. If you need more help, comment and I'll be more than glad to assist you! :P

8 0

3 years ago

2. (01.02 MC)

Deffense [45]

Bisecting a line segment or an angle segment would divide the line (or the angle) into equal segments

<h3>The similarities in their constructions</h3>

The similarity in the constructions is that, both constructions are bisections, and they are meant to divide the segments into equal sectors

<h3>The differences in their constructions</h3>

The differences in the constructions is that, Anton's construction step would bisect a line, while Maxim's construction step would bisect an angle

What is the exponential expression for the numerical expression ​ 5⋅5⋅5⋅5 ​ ?

What is the exponential expression for the numerical expression 5⋅5⋅5⋅5 ?