Answer:
Step-by-step explanation:
hypotenuse=2*AB
where AB is the smallest side.
Take AB as the base .
Draw a perpendicular at B.
A as the center and cut an arc AC=2 AB
Join AC.
CAB is the reqd. triangle.
Answer:
answer A
Step-by-step explanation:
hello,

hope this helps
Imagine the unit circle. The cot(theta) is a line from (0,1) to (-4,1). Imagine it is part of a triangle with the origin (draw it!).
Then the hypotenuse length is √(1+4²) = √17.
The sine rule says that sin(90)/√17 must equal sin(theta)/4, and sin(90)=1, so
Answer:
x < -4 ∪ x > 4
Step-by-step explanation:
The absolute value function is shifted down 3 units. The solution space is values of x where y = |x|-3 is greater than 1. The solution is shown in red in the attachments, and the left and right (dashed) sides of the inequality are shown in blue.
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I personally prefer to rewrite the inequality so the comparison is to <em>zero</em>. That is done in the second attachment, which rewrites it to ...
|x| -4 > 0
by subtracting 1 from both sides. It is often easier to read the values of x-intercepts than it is to read the coordinate values where lines cross each other.
<u>ANSWER</u>

<u>EXPLANATION</u>
The given function is

We make the coefficient of
unity by factoring
out of the last two terms to obtain;

We now add and subtract half the coefficient of
multiplied by a factor of 6 to obtain;

We now factor 6 out of the last two terms to get;


The quadratic trinomial in the parenthesis is now a perfect square.

Hence the vertex form of the polynomial is
