We can draw this as:
We can use the Pythagorean theorem to find the length of the cable, as it is the hypotenuse of a right triangle:
![\begin{gathered} c^2=7^2+8^2 \\ c^2=49+64 \\ c^2=113 \\ c=\sqrt[]{113} \\ c\approx10.63 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3D7%5E2%2B8%5E2%20%5C%5C%20c%5E2%3D49%2B64%20%5C%5C%20c%5E2%3D113%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B113%7D%20%5C%5C%20c%5Capprox10.63%20%5Cend%7Bgathered%7D)
Answer: the cable length is 10.63 m.
Answer:
60 cm2
Step-by-step explanation:
15x4=60
Step-by-step explanation:

plzzz.. .......
mark it as a brilliant answer
Start here: A = 18 ft^2 = L * W. Next, L = 2W.
Merging these 2 formulas lets us eliminate L:
18 ft^2 = (2W) * (W) = 2W^2.
So W^2 = 9 ft^2, and W=3 ft. Please use L = 2W (from above) to calculate L.
The correct answer is is the option B . X>0
Hopefully this help you