Answer:
x = 3, y = - 2
Step-by-step explanation:
By substitution method,
4x + y = 10 -------> equation 1.
7x + 2y = 17 -------> equation 2.
From equation 1,
y = 10 - 4x ------> equation 3.
Substitute equation 3 in 2,
7x + 2 ( 10 - 4x ) = 17
7x + 20 - 8x = 17
7x - 8x = 17 - 20
- x = - 3
x = 3
Substitute x = 3 in equation 1,
4 ( 3 ) + y = 10
12 + y = 10
y = 10 - 12
y = - 2
Hence,
x = 3
y = - 2
We can't use P = 2L + 2W because the sides have different lengths.
P = a + b + c + d
a = x
b = 2x
c = 2x - 2
d = x + 5
P = x + 2x + (2x - 2) + (x + 5)
P = <u>x + 2x + 2x</u> - 2 <u>+ x</u> + 5
P = 6x + 3
if x = 4:
P = 6 · 4 + 3
P = 24 + 3
P = 27
Answer:
Step-by-step explanation:
y=3x-2, plug in each for x and y on the table and they work
Answer:
A) x = 3 or -1
B) x = -7
C)x = -7
Step-by-step explanation:
A) x² + 2x + 1 = 2x² - 2
Rearranging, we have;
2x² - x² - 2x - 2 - 1 = 0
x² - 2x - 3 = 0
Using quadratic formula, we have;
x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)
x = (2 ± √16)/2
x = (2 + 4)/2 or (2 - 4)/2
x = 6/2 or -2/2
x = 3 or -1
B) ((x + 2)/3) - 2/15 = (x - 2)/5
Multiply through by 15 to get;
5(x + 2) - 2 = 3(x - 2)
5x + 10 - 2 = 3x - 6
5x - 3x = -6 - 10 + 2
2x = -14
x = -14/2
x = -7
C) log(2x + 3) = 2log x
From log derivations, 2 log x is same as log x²
Thus;
log(2x + 3) = logx²
Log will cancel out to give;
2x + 3 = x²
x² - 2x - 3 = 0
Using quadratic formula, we have;
x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)
x = (2 ± √16)/2
x = (2 + 4)/2 or (2 - 4)/2
x = 6/2 or -2/2
x = 3 or -1
Answer:
A =21
B=125
C=34
Step-by-step explanation:
