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3 years ago

BRAINLIESTTT ASAP!! Who take FLVS Chemistry ( Seg 1) ? Please only answer if you do. :)

Mathematics

1 answer:

alexandr1967 [171]3 years ago

3 0

Answer: I took it last year as a junior, what is the questions tho?

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Which value is equivalent to 48 ÷ ((2 + 6) × 2) − 1?

nalin [4]

Answer:

Step-by-step explanation:

use PEMDAS=

2+6=12

12x2=24

48/24=2

2-1= 1

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3 years ago

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Help pls <br> 8 + 6x = -4

gavmur [86]

Answer:

x=-2

Step-by-step explanation:

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Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

$\:\:y=\:\left(x-5\right)^3-1$

$-3\:=\:\left(x-5\right)^3-1\:\:\:$

switch sides

$\left(x-5\right)^3-1=-3$

Add 1 to both sides

$\left(x-5\right)^3-1+1=-3+1$

$\left(x-5\right)^3=-2$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

$x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}$

And the real input is:

$x=-\sqrt[3]{2}+5$

$x=3.74$

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3 years ago

Which image is a reflection of the black polygon in quadrant I?

Vadim26 [7]

Answer:

the red polygon in quadrant II

Step-by-step explanation:

It makes the most sense polygon 4 is not the answer because if we reflected it would be upside down, try to image a mirror in front of polygon 1 it would reflect to polygon 2 make the answer quadrant II.

Please Brainliest :D

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BC is tangent to circle A. Determine the length of AC.

sweet-ann [11.9K]

Answer:

Step-by-step explanation:

AC=√(3^2+4^2)=√(9+16)=√(25)=5

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2 years ago