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elena-14-01-66 [18.8K]
3 years ago
9

The function f(x) is graphed on the coordinate plane. What is f(−4) ?

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0
For this type of problem, plug the -4 into the graph for x. So where is the line at x = -4??
y = 4 where x = -4.
That's the same as saying: "what is the y-value when x = -4?)
f(-4) = y = 4
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HELP ME THIS IS DUE TMR
Amanda [17]

Answer:

Rational, irrational, irrational, rational.

Step-by-step explanation:

It's a negative number.

It repeats forever

It repeats forever

It's equivalent to 8

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What is the relationship between 0.8 ÷ 10^2 and 0.8×10^2
AleksandrR [38]

0.8\times10^2\ \text{is 10,000 times greater than}\ 0.8\div10^2\\\\\dfrac{0.8\times10^2}{0.8\div10^2}=\dfrac{10^2}{1\div10^2}=\dfrac{10^2}{\frac{1}{10^2}}=10^2\times10^2=10^4=10,000

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3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%
SVETLANKA909090 [29]

\huge \boxed{\mathbb{QUESTION} \downarrow}

\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)

The remaining elements of the product matrix are found in the same way.

\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)

Simplify each element by multiplying the individual terms.

\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)

Now, sum each element of the matrix.

\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}

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3 years ago
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Scorpion4ik [409]

Answer:

B

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liq [111]

Answer:

2

Step-by-step explanation:

3(x+2)=12

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Subtract:

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3x=6

Divide:

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4 0
3 years ago
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