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Nana76 [90]
3 years ago
14

An urn contains r red balls and b blue balls. One ball is selected at random from this urn, its color is recorded and it is retu

rned to the urn along with m additional balls of the same color as chosen. Another single ball is randomly selected from the urn (now containing r b m balls) and it is observed that the ball is blue. What is the conditional probability that the first ball selected is red given that the 2nd ball selected is observed to be blue?
Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

Zero

Step-by-step explanation:

The probability of the ball being red after first selection is = (r) ÷ (r+b)

The probability of the ball being blue after first selection is = (b) ÷ (r+b)

If the ball selected is red, the total number of balls after its returned together with m number of red balls is = r+b+m

The probability of the  selection doesn't depend on the second selection, hence condition probability is zero.

However the probability of the second selection depends on the first selection.

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Select the two values of x that are roots of this equation 3x^2 + 1 =5x
Zina [86]

Answer:

x = 1.434 and x=0.232

Step-by-step explanation:

To find the root of the equation stated above we need to:

(1) Write the polynomial equation with zero on the right hand side:

3x^{2} + 1 = 5x ⇒ 3x^{2} -5x + 1 = 0

(2) Divide the whole equation by 3

3x^{2} -5x + 1 = 0 ⇒ x^{2} -\frac{5}{3}x + \frac{1}{3}= 0

(3) Use the quadratic formula to solve the quadratic equation:

The quadratic formula states that the two solutions for a quadratic equation is given by:

\frac{-b±\sqrt{b^{2} - 4ac}}{2a} (1)

In this case, a = 1, b = -\frac{5}{3}, c= \frac{1}{3}

Substituiting a, b and c in equation (1) We get:

\frac{-\frac{5}{3}±\sqrt{(-\frac{5}{3})^{2} - 4(1)(\frac{1}{3})}}{2(1)} (1)

The two solutions are:

x = 1.434 and x=0.232

8 0
2 years ago
A cell phone provider offers a plan that costs ​$30 per month plus ​$0.10 per text message sent or received. A comparable plan c
mariarad [96]

300 messages would have to be sent or received in order for the plan to cost same each month.

Step-by-step explanation:

Given,

Cost per month = $30

Per text sent or received charges = $0.10

Let,

x be the number of texts sent or received.

A(x) = 0.10x+30    

A comparable plan costs = $60 per month

Text messages are unlimited.

B(x) = 60

For the two plans to cost equal;

A(x) = B(x)

0.10x+30=60\\0.10x=60-30\\0.10x=30

Dividing both sides by 0.10

\frac{0.10x}{0.10}=\frac{30}{0.10}\\x=300

300 messages would have to be sent or received in order for the plan to cost same each month.

Keywords: function, addition

Learn more about functions at:

  • brainly.com/question/2860697
  • brainly.com/question/2977815

#LearnwithBrainly

3 0
3 years ago
Find the value of X.
hram777 [196]

Answer:

X=6 I believe

Step-by-step explanation:

3 0
3 years ago
Best and Correct answer gets BRAINLIEST!!!!!
Aleks [24]
A is the answer!! Hope it helps
5 0
2 years ago
X=a<br> There were 120 problems.'<br> You got two-fifths wrong.<br> How many did you get right?
swat32

120 x 2 = 240

240/5 = 48

120 - 48 = 72

Answer is 72.

You got 72 correct.

7 0
2 years ago
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