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Lynna [10]
4 years ago
11

PLEASE HELP!! ASAP NOWWWW Two races that a student runs every year are the 1492​-mile race in his hometown and the ​-meter race

in his college town. Complete parts​ (a) through​ (d) below.

Mathematics
1 answer:
Softa [21]4 years ago
3 0

Answer:

College town race is 31% of the home town race.

Step-by-step explanation:

Length of hometown race = 3 miles

Length of college town race = 1492 meters

Since 1 meter = 0.0006214 miles

Therefore, 1492 = 0.93 miles

Percentage of college town race to the hometown race,

= \frac{\text{College town race}}{\text{Home town race}}\times 100

= \frac{0.93}{3}\times 100

= 31%

Therefore, the college town race is 31% of the home town race.

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The distance from Earth to the moon is estimated to be 2.52 x 105 miles. The distance from Earth to the sun is approximately 400
chubhunter [2.5K]

Answer: 9\times10^7\ miles


Step-by-step explanation:

Given: The estimated distance from Earth to the moon=2.25\times10^5\ miles

If the distance from Earth to the sun is approximately 400 times farther.

Then, the distance from Earth to the sun=400\times2.25\times10^5

=900\times10^5\ miles\\=9\times10^7\ miles

Therefore, the approximate distance from Earth to the sun=9\times10^7\ miles

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4 years ago
A rectangular tank, 25 cm long and 25 cm wide is filled with water to a depth of 10 cm. When a metal cube of edge 10 cm is place
Sophie [7]

The problem involves the volume of the water of the rectangular tank, so first we must find the volume of our water. For the volume we have;

\begin{gathered} \text{Volume = Lenght x Width x Height} \\ V_{water}_{}_{}\text{ = 25 x 25 x 10} \\ V_{water}=6250cm^3 \end{gathered}

Therefore our tank has an initial volume of 6250 cm³, but if you drop a cube with a side measuring 10 cm. the volume of the water in our tank increases. Giving us the expression;

\begin{gathered} \text{Volume Combined = Volume of Water + Volume of Cube} \\ V_{comb}=V_{water}+V_{cube} \end{gathered}

Since we already have the volume of the water (which is 6250), we just need to find the volume of the cube using the same formula (<em>Volume = Lenght x Width x Height</em>);

\begin{gathered} V_{comb}=V_{water}+V_{cube} \\ V_{comb}=V_{water}+(Lenght_{cube})(Width_{cube})(Height_{cube})_{}_{}_{} \\ V_{comb}=V_{water}+10(10)(10) \\ V_{comb}=6250+1000 \\ V_{comb}=7250cm^3 \end{gathered}

Therefore our new volume when they are combined or when the cube is droped in the tank is 7250 cm³.

But we must remember since our tank would remain it's shape no matter how much water it holds it would always retain it's dimension of it's lenght and width (25x25), therefore it is possible to find the height of the new water level using this logic;

\begin{gathered} V_{comb}=(Length_{\tan k})(Width_{\tan k})(Height_{water}\text{)} \\ V_{comb}=(25)(25)(Height_{water})\text{ , with our }V_{comb}=7250 \\ 7250=625(Height_{water}) \\ \text{Height}_{water}=\frac{7250}{625} \\ \text{Height}_{water}=11.6\text{ cm} \end{gathered}

Therefore the height of the new water level is 11.6 cm.

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48 inches is the answer
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