Answer:
y -8 = -5(x -6)
Step-by-step explanation:
The point-slope form of the equation for a line is generally written ...
y -k = m(x -h)
for slope m and point (h, k).
The slope of your parallel line is the same as the slope of the reference line, -5. So your equation is ...
y -8 = -5(x -6)
Answer:
Algebra Examples
Popular Problems Algebra Find the Axis of Symmetry f(x)=x^2-5 f(x)=x2−5 Set the polynomial equal to y to find the properties of the parabola. y=x2−5
Rewrite the equation in vertex form.
y=(x+0)2−5 Use the vertex form, y=a(x−h)2+k, to determine the values of a, h, and k.a=1h=0k=−5
Since the value of a is positive, the parabola opens up.
Opens Up
Find the vertex
(h,k).(0,−5)
Find p, the distance from the vertex to the focus.
14 Find the focus.
(0,−194)
Find the axis of symmetry by finding the line that passes through the vertex and the focus.
x=0
According to given figure, The Triangle BDC is a right angled Triangle (Angle D = 90°)
So, we can apply Pythagoras theorem to find the Side a (Hypotenuse)
Now, let's solve ~
Therefore, Length of side a is 5 units ~
Answer:
X = 5
Step-by-step explanation:
Here is what I am picturing (not to scale)
A ----------------B-----------C
We are given the information of AB (which equals 3x + 1), BC (which equals 4x - 5), and AC (which equals 8x - 9).
With reference to the line, AB + BC = AC
So,
3x + 1 + 4x - 5 = 8x - 9
7x - 4 = 8x - 9
5 = x
Answer: Jenny
Step-by-step explanation:
By subtitue Y = 0
0=(x-3)^2
And you get 3
