3 years ago

Find the angle between the given vectors to the nearest tenth of a degree u I =, v =

1 answer:

4 0

I’m confused I do t see anything

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Yuki888 [10]

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Fourth one i think (the way u typed the q is confusing)

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Anika [276]

Answer:

Step-by-step explanation:

Our values are:

N = 100,000 (We assume it)

Proportion is p = 0.6

Margin of error (E) = 0.05

confidence-level (cl) = 0.95

Z-value = 1.96

We need to approach through Proportion,

$n=\frac{ (z_2 * p *q) + ME_2}{ME_2 + z_2 * p * q / N}$

Substituting,

$n = \frac{(1.962*0.6*0.4)+0.052}{0.052 + \frac{1.962 * 0.6 * 0.4}{100000}}$

$n= \frac{(3.841 * 0.24)+0.0025}{0.0025+\frac{3.841*0.24}{100000}}$

$n =\frac{ 0.9243}{0.002509}$

$n= 368$

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Debora [2.8K]

Sam kept his account open for 2 days.

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