Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere
The differential of V with respect to r is:
dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
Answer:
x = 1 ±√89
Step-by-step explanation:
We have the equation:
(x+7)(x-9) = 25
Using distributive property:
x(x-9) + 7(x-9) = 25
x²- 9x + 7x - 63 -25 = 0
x²- 2x - 88 = 0
To complete squares we need to add and subtract 1, as follows:
x²- 2x - 88 +1 -1 = 0
x²- 2x +1 -88 -1 = 0 (this is a perfect square)
(x - 1)² - 89 = 0
Solving for x:
(x - 1)² = 89
x - 1 = ±√89
x = 1 ±√89
Answer:
2.44
Step-by-step explanation:
12 1/2 / 5 =2.44
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