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2 years ago

PLEASE I NEED HELP!

Mathematics

2 answers:

N76 [4]2 years ago

4 0

Answer:Complete the statements.

When r = 2, the first expression is . 6

When r = 2, the second expression is 6.

When r = 5, the first expression is 21.

When r = 5, the second expression is .

The expressions are not equivalent. 12

Step-by-step explanation:

i got it right on e d g e n u i t y

Step-by-step explanation:

NARA [144]2 years ago

3 0

Fourth one i think (the way u typed the q is confusing)

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-2/17x=10 what is the solution set?

puteri [66]

Answer:

x=-85

Step-by-step explanation:

7 0

2 years ago

Please help me its about solving system by substitution

Andrew [12]

Answer:

(-3, 4)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Terms/Coefficients
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = -x + 1

2x + 3y = 6

Step 2: Solve for x

Substitution

Substitute in y: 2x + 3(-x + 1) = 6
Distribute 3: 2x - 3x + 3 = 6
Combine like terms: -x + 3 = 6
Isolate x terms: -x = 3
Isolate x: x = -3

Step 3: Solve for y

Define equation: y = -x + 1
Substitute in x: y = -(-3) + 1
Simplify: y = 3 + 1
Add: y = 4

6 0

2 years ago

Whay is -240 divided by -36

kherson [118]

7 because you have to round 6 to 7 from the former seven and seven is bigger than 4 so the 6 would become a

7

8 0

2 years ago

Read 2 more answers

Y -13 --------- = y -7

mario62 [17]

y-13 / y-7

cross multiply

y-13 = y-7

collect like terms

y+y =-7+13

2y= 13 -7

2y = 6

divide both sides by 2

2y/ 2y = 6/2

y= 3

I hope this helped

4 0

3 years ago

Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

3 0

2 years ago