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andre [41]
3 years ago
13

To which real number subsets do the following real numbers belong?

Mathematics
1 answer:
andrezito [222]3 years ago
6 0

pretty sure the answer is b

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A project to build a new bridge seems to be going very well since the project is well ahead of schedule and costs seem to be run
Alecsey [184]

Answer:

Scheduled Variance = $850,000.00

Schedule Performance Index = 1.05

Cost Performance Index = 1.11

Step-by-step explanation:

Note: See the attached excel file for the calculations of Total Actual Cost to Date, Budgeted Cost of Work Scheduled (BCWS), and Budgeted Cost of Work Performed (BCWP).

From the attached excel file, we have:

Total Actual Cost to Date = $15,300,000

Total BCWS = $16,170,000

Total BCWP = $17,020,000

Therefore, we have:

Scheduled Variance = Total BCWP - Total BCWS = $17,020,000 - $16,170,000 = $850,000.00

Schedule Performance Index = Total BCWP / Total BCWS = $17,020,000 / $16,170,000 = 1.05

Cost Variance = Total BCWP - Total actual cost to date = $17,020,000 - $15,300,000 = $1,720,000

Cost Performance Index = Total BCWP / Total actual cost to date = $17,020,000 / $15,300,000 = 1.11

Download xlsx
7 0
2 years ago
Find the holes<br> <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7Bx%2B3%7D%7B%28x%2B1%29%28x-2%29%7D" id="TexFormula1" t
olga55 [171]

Answer:

<h2>           x=-1 and x=2</h2>

Step-by-step explanation:

The "holes" are the x-es where function doesn't exist.

one must not divide by 0, so given function doesn't exis if the denominator is equal 0

The product {(x+1)×(x-2)} is equal 0 if any of factors  {(x+1),(x-2)} is 0, so

x + 1 = 0    or    x - 2 = 0

x = - 1      or    x = 2

8 0
2 years ago
What is the length of the line segment whose endpoints are (1, 1) and (3, - 3)
Shtirlitz [24]

Answer:

length= √[ (a-c)^2 + (b-d)^2 ]

Step-by-step explanation:

5 0
2 years ago
A fast-food company is interested in knowing the probability of whether a customer viewed an advertisement for their new special
lord [1]

Answer:

45% probability that a randomly selected customer saw the advertisement on the internet or on television

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a customer saw the advertisement on the internet.

B is the probability that a customer saw the advertisement on television.

We have that:

A = a + (A \cap B)

In which a is the probability that a customer saw the advertisement on the internet but not on television and A \cap B is the probability that the customers saw the advertisement in both the internet and on television.

By the same logic, we have that:

B = b + (A \cap B)

12% saw it on both the internet and on television.

This means that A \cap B = 0.12

20% saw it on television

This means that B = 0.2

37% of customers saw the advertisement on the internet

This means that A = 0.37

What is the probability that a randomly selected customer saw the advertisement on the internet or on television

A \cup B = A + B - (A \cap B) = 0.37 + 0.2 - 0.12 = 0.45

45% probability that a randomly selected customer saw the advertisement on the internet or on television

6 0
3 years ago
Is it true or false that a bbinomial can have a degree of zero?
Mumz [18]

No, because any real valued term with degree 0 would be a constant. All constants in an expression can be combined into single term. Therefore if the expression were of degree 0, all the terms would be constants and could be combined into a single term making the expression a monomial.

6 0
3 years ago
Read 2 more answers
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