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3 years ago

Mary high school played 823 baseball games this year .she attended 481 games. how many games did Mary missed?

Mathematics

1 answer:

Alborosie3 years ago

5 0

It’s simple subtraction the answer is 342

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How to work out ratio

-Dominant- [34]

Answer:

To work out how much each person gets you then multiply theirshare by 100.

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2 years ago

Can someone please help me with this problem:(

Flauer [41]

Answer:

x y

-2 4

0 0

1 -2

2 4

Step-by-step explanation:

in the equation replace x with the number from the table in the x colum then complete the equation

7 0

3 years ago

Solve 9y = 27 How can you find the value of y

Bumek [7]

You need to divide 9 to both sides in order for y to come alone. So then you would have to divide 27 by 9 and y = 3. Hope this helps!

6 0

3 years ago

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago

-(4-8n) -7n = help meeeeeeeeee

romanna [79]

Answer:

-4+n

Step-by-step explanation:

-4+8n-7n=

4 0

2 years ago

Mary high school played 823 baseball games this year .she attended 481 games. how many games did Mary missed?​

Mary high school played 823 baseball games this year .she attended 481 games. how many games did Mary missed?