Molarity is defined as number of moles of solute in 1 L of solution.
Here, 0.1025 g of Cu is reacted with 35 mL of HNO_{3} to produced Cu^{2+} ions.
The balanced reaction will be as follows:
Cu+3HNO_{3}\rightarrow Cu(NO_{3})_{2}+NO_{2}+H_{2}O
From the above reaction, 1 mole of Cu produces 1 mole of Cu^{2+}, convert the mass of Cu into number of moles as follows:
n=\frac{m}{M}
molar mass of Cu is 63.55 g/mol thus,
n=\frac{0.1025 g}{63.55 g/mol}=0.0016 mol
Now, total molarity of solution, after addition of water is 200 mL or 0.2 L can be calculated as follows:
M=\frac{n}{V}=\frac{0.0016 mol}{0.2 L}=0.008 mol/L=0.008 M
Thus, molarity of Cu^{2+} is 0.008 M.
The statement above about "<span>The reduction in the freezing point of a solution is inversely proportional to a molal concentration" is false. It must be directly proportional</span>
Q=mc(change in temp)
Q is amount of heat, m is mass, c is specific heat
Water:
Q= (50.0g)(4.18 J/g°C)(63°C)
Q= 13167J
Aluminum:
Q= (200.0g)(0.900 J/g°C)(63°C)
Q= 11340J
Water requires more heat
In a 2.2 m solution with the same volume there would be 11.825 g of a salt
I believe the answer is 4 carbons. Glycolysis involves break down of glucose to two molecules of pyruvic acid (3 carbons) under aerobic conditions. At the end of glycolysis the two pyruvate molecules undergoes pyruvate oxidation to capture the remaining energy in the form of ATP. A carboxyl group is removed from pyruvate and released in the form carbon dioxide, leaving a two carbon molecule which forms Acetyl-CoA (2 molecules). Acetyl-CoA then serves as a fuel for the citric acid cycle in the next stage of cellular respiration.
