The compound is 82.76% C and 17.24% H
In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.
<h3>Describe the empirical formula.</h3>
The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea.
The simplest whole number ratio of each type of atom in a compound is its empirical formula. It can be determined from data on the mass of each component in a compound or from the composition's proportion.
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Answer:
Energy lost is 7.63×10⁻²⁰J
Explanation:
Hello,
I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5
E = hc/λ(1/n₂² - 1/n₁²)
n₁ = 15
n₂ = 5
hc/λ = 2.18×10⁻¹⁸J (according to the data)
E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)
E = 2.18×10⁻¹⁸ (1/15² - 1/5²)
E = 2.18×10⁻¹⁸ ×(-0.035)
E = -7.63×10⁻²⁰J
The energy lost is 7.63×10⁻²⁰J
Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level
Answer:
luster
i just did it and its luster
Answer: 12 ( answer not among the option)
Explanation:
From the equation of reaction; P4O10+ H2O -----> H3PO4, it is unbalanced.
One can only get the exact number of ''Hydrogen atom'' if it is well balanced.
Adding '4' to H3PO4 on the RHS and '6' to H2O on LHS of the equation would give a balanced equation such as;
P4O10 + 6H2O -----> 4 H3PO4
Therefore the number of hydrogen atoms found on the reactant is 12.
She would divide that mass of each element by it molar mass the answer is C <span />
