3 years ago

When she carried out her experiment, Tanya used three small vials of the

Chemistry

1 answer:

sleet_krkn [62]3 years ago

8 0

It’s a I hope it rightgood luck

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A 3.20-mol sample of gas occupies a volume of 350. mL at 300.0 K. Determine the

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Answer:

$P \approx 225atm$

Explanation:

From the question we are told that:

Moles of sample n=3.20_mol

Volume V=350mL

Temperature T=300k

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

$P=\frac{nRT}{V}$

$P=\frac{3.20*0.08206*300}{350*10^{-3}}$

$P=225.079atm$

$P \approx 225atm$

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3 years ago

Have an infinite number of significant figures

vovikov84 [41]

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A student climbed up the hill at a constant speed, stopped at the top, and then ran quickly down the other side.

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The Answer Is C

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2 years ago

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The combustion of butane produces heat according to the equation 2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(l), ΔH°rxn= –5,314 kJ/mol

Dafna11 [192]

Answer:

665 g

Explanation:

Let's consider the following thermochemical equation.

2 C₄H₁₀(g) + 13 O₂(g) → 8 CO₂(g) + 10 H₂O(l), ΔH°rxn= –5,314 kJ/mol

According to this equation, 5,314 kJ are released per 8 moles of CO₂. The moles produced when 1.00 × 10⁴ kJ are released are:

-1.00 × 10⁴ kJ × (8 mol CO₂/-5,314 kJ) = 15.1 mol CO₂

The molar mass of CO₂ is 44.01 g/mol. The mass corresponding to 15.1 moles is:

15.1 mol × 44.01 g/mol = 665 g

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Magnesium carbonate decomposes on heating to form magnesium oxide and carbon dioxide as shown.

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C. 21.0g

that’s the aweeee

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