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Vikki [24]
3 years ago
9

Please help me, I’ll give brainliest

Mathematics
1 answer:
kolbaska11 [484]3 years ago
7 0

Answer:

<em>x</em><em> </em><em>=</em><em> </em><em>4</em><em>5</em>

<em>y</em><em> </em><em>=</em><em> </em><em>5</em>

Step-by-step explanation:

<em>it</em><em> </em><em>is</em><em> </em><em>b</em><em>ecause</em>

<em>9</em><em>0</em><em>/</em><em>2</em><em> </em><em>=</em><em> </em><em>4</em><em>5</em>

<em>(</em><em>9</em><em>0</em><em>+</em><em>1</em><em>0</em><em>)</em><em>/</em><em>2</em><em>0</em><em> </em>

<em>(</em><em>1</em><em>0</em><em>0</em><em>)</em><em>/</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>,</em><em>5</em>

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Draw a line representing the "run" and a line representing the "rise" of the line. State the slope of the line in simplest form.
Shtirlitz [24]

Answer:

\displaystyle 1\frac{1}{3}

Step-by-step explanation:

[3, 1] and [0, −3]

\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{3 + 1}{0 + 3} = \frac{4}{3} = 1\frac{1}{3}

I am joyous to assist you anytime.

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Which is the value of 9x - 5 when x = 8?
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when x = 8

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Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=
Ganezh [65]

Answer:

y(1+x)+x-5\ln xy=C

Step-by-step explanation:

Consider the given differential equation is

(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1

(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y

(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx

Taking all variables on right sides.

(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0

(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0

Let as assume,

M=-\frac{5}{x}+1+y and N=1-\frac{5}{y}+x

Find partial derivatives \frac{\partial M}{\partial y} and \frac{\partial N}{\partial x}

\frac{\partial M}{\partial y}=1 and \frac{\partial N}{\partial x}=1

Since \frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}, therefore the given differential equation is exact.

The solution of the exact differential equation is

\int Mdx+\int N(\text{without x)}dy=C

\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C

yx-5\ln x+x+y-5\ln y=C

y+x+xy-5\ln x-5\ln y=C

y(1+x)+x-5(\ln x+\ln y)=C

y(1+x)+x-5\ln xy=C

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Write 58 1/2 in radical form
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58^(1/2) is √58 if that is what you meant
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Which equation represent a relationship where y is a nonlinear function of x? Select all that apply
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