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Aleks04 [339]
3 years ago
9

Please HELP!!!!

Mathematics
1 answer:
dedylja [7]3 years ago
8 0
Absolute value equations have more than one solution because when the answer is in abs. value, it is positive, so there could be a negative answer and it would still be positive. For example |-5|=5 and |5|=5 as well. 
4+|2x|=-1 would have no solution because you cannot have the equation equal a negative since the 2x is in absolute value. 
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add 3 to they coordinate

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Is x = -12 a solution of x^2 +10x+25=49?
Tresset [83]

Answer:

Yes

Step-by-step explanation:

{x}^{2}  + 10x + 25 = 49 \\  {x}^{2}  + 10x + 25 - 49 = 0 \\  {x}^{2}  + 10x - 24 = 0 \\ (x + 12)(x -2 ) = 0 \\  \\ x  + 12 = 0 \\ x =  - 12 \\  \\  \\ x  - 2 = 0 \\x = 2

I hope I helped you^_^

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Evaluate (2-3) (4) - 9 -3.<br> -7<br> I<br> 11<br> 4
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Answer:

-16

Step-by-step explanation:

8 0
3 years ago
A bowling ball is pushed with a force of 22.0 N and accelerates at 5.5 m/s2. What is the mass of the bowling ball? Ik the answer
KiRa [710]

Step-by-step explanation:

You should always use the least number of significant figures.  The exception is exact numbers or constants.

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5 0
3 years ago
A theatre group sold a total of 440 tickets for a show, making a total of $3940. Each regular ticket cost $5, each premium ticke
valentina_108 [34]

Answer: 330 regular tickets, 46 premium tickets and 64 elite tickets were sold.

Step-by-step explanation:

Let x represent the number of regular tickets that were sold.

Let y represent the number of premium tickets that were sold.

Let z represent the number of elite tickets that were sold.

The theatre group sold a total of 440 tickets for the show. It means that

x + y + z = 440- - - - - - - - - -1

Each regular ticket cost $5, each premium ticket cost $15, and each elite ticket cost $25. The total amount made from the show was $3940. It means that

5x + 15y + 25z = 3940- - - - - - - - - 2

The number of regular tickets was three times the number of premium and elite tickets combined. It means that

x = 3(y + z)

x = 3y + 3z

Substituting x = 3y + 3z into equation 1 and equation 2, it becomes

3y + 3z + y + z = 440

4y + 4z = 440- - - - - - - - - - - - -3

5(3y + 3z) + 15y + 25z = 3940

15y + 15z + 15y + 25z = 3940

30y + 40z = 3940 - - - - - - - - - - 4

Multiplying equation 3 by 10 and equation 4 by 1, it becomes

40y + 40z = 4400

30y + 40z = 3940

Subtracting, it becomes

10y = 460

y = 460/10

y = 46

Substituting y = 46 into equation 3, it becomes

4 × 46 + 4z = 440

184 + 4z = 440

4z = 440 - 184

4z = 256

z = 256/4

z = 64

x = 3(y + z) = 3(46 + 64)

x = 330

4 0
3 years ago
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