Answer:
how many eggs will 12 eggs lay ???
Step-by-step explanation:
Answer:
Assume x is directly proportional to y :
![y \: \alpha \: x \\ y = kx](https://tex.z-dn.net/?f=y%20%5C%3A%20%20%5Calpha%20%20%5C%3A%20x%20%5C%5C%20y%20%3D%20kx)
when y is 9, x is 2:
substitute to find value of k :
![9 = (k \times 2) \\ k = \frac{9}{2}](https://tex.z-dn.net/?f=9%20%3D%20%28k%20%5Ctimes%202%29%20%5C%5C%20k%20%3D%20%20%5Cfrac%7B9%7D%7B2%7D%20)
Therefore, equation is:
![{ \boxed{ \boxed{2y = 9 x}}}](https://tex.z-dn.net/?f=%7B%20%5Cboxed%7B%20%5Cboxed%7B2y%20%3D%209%20x%7D%7D%7D)
Answer:
9/10
Step-by-step explanation:
Very simple, Keep It, Change It, Flip it
Do 3/4 X 6/5 and you should get your answer
I believe the answer is D.
No, it is not a proportional relationship because the graph does not go through the origin.
Answer:
![x=14](https://tex.z-dn.net/?f=x%3D14)
Step-by-step explanation:
The given triangle is a right triangle, meaning it is a triangle with a right angle, this is indicated by the box around one of the angles. When given a right triangle, one can use the right triangle trigonometric ratios. These ratios describe the relationship between an angle in a right triangle, and the sides in a right triangle. Such ratios are as follows,
![sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D%5C%5C%5C%5Ccos%28%5Ctheta%29%3D%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D%5C%5C%5C%5Ctan%28%5Ctheta%29%3D%5Cfrac%7Bopposite%7D%7Badjacent%7D)
Bear in mind that the way one names the sides, in the sense of (opposite or adjacent) will change based on the angle one uses to describe the triangle. However, the hypotenuse is the same no matter the angle, as the hypotenuse is the side opposite the right angle.
In this case, one is given one of the angles, and the side opposite the angle. One is asked to find the hypotenuse of the triangle. One can use the sine (sin) ratio to achieve this.
![sin(\theta)=\frac{opposite}{hypotenuse}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D)
Substitute,
![sin(30)=\frac{7}{x}](https://tex.z-dn.net/?f=sin%2830%29%3D%5Cfrac%7B7%7D%7Bx%7D)
Inverse operations,
![x=\frac{7}{sin(30)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B7%7D%7Bsin%2830%29%7D)
Simplify,
![x=14](https://tex.z-dn.net/?f=x%3D14)