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IRINA_888 [86]
2 years ago
14

A right-angled triangle has a hypotenuse of length 8 and another side of length 3.

Mathematics
1 answer:
erica [24]2 years ago
4 0

Answer:

The file contains the solution to the above question

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4x+25=57<br>valor de x por favor​
sukhopar [10]

Answer:

4x=8

Step-by-step explanation:

4x=32

32/4=8

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3 years ago
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Identify the error in the student solution shown below. Find the correct answer.
AlexFokin [52]

Answer:

Step-by-step explanation:

The answer is Since 0 in ln(3x) - 0 is not a logarithm, the property of logarithms cannot be used here.

The difference shown cannot be written as a quotient of logarithms.

The step ln(x2) = ln(3x) - (0) reduces to

ln(x2) = ln(3x).

The possible solutions are 0 and 3, with 0 being extraneous.

7 0
3 years ago
Find the y-intercept of the line: 2x + 4y = 8
romanna [79]

Answer:

(4, 0)

Step-by-step explanation:

2x + 4y = 8

x-intercept when y = 0

2x = 8

x = 4

so x-intercept (4, 0)

:) hole this helps

6 0
2 years ago
5x4 - 29x3 +21x2 - 8x + 15<br> X-5
Helga [31]

Answer:

5x^4−29x^3+21x^2+7x−5

Step-by-step explanation:

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5 0
3 years ago
In ΔJKL, k = 3.7 cm, ∠K=15° and ∠L=41°. Find the length of j, to the nearest 10th of a centimeter.
Alexandra [31]

Answer:

The length of side j is 11.85cm

Step-by-step explanation:

Given that

In triangle JKL,

\angle k=15

\angle l=41

Side k=LJ=3.7cm

To find side j=KL:

By using sine rule,

We can write as

\frac{SinK}{LJ} = \frac{SinL}{JK} = \frac{SinJ}{KL} \\\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{SinJ}{KL}

Using property of triangle,

\angle k+\angle l+\angle j=180

15+41+\angle j=180

\angle j=124

\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{Sin124}{KL}\\\frac{Sin15}{3.7} = \frac{Sin124}{KL}\\KL=3.7\frac{Sin124}{Sin15}\\KL=3.7\frac{0.8290}{0.2588}\\KL=11.85cm

Thus,

The length of side j is 11.85cm

8 0
3 years ago
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