According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
Answer:
(-5,2), (-5,4), and (-1,1)
Step-by-step explanation:
Pretty sure it would be 22.
17+7^2=66
17-2(7)=3 and you would divide 66 by 3
Answer: 47
4•|11|+3
44+3
=47