Answer:
Step-by-step explanation:
![-2\dfrac{1}{3}-1\dfrac{1}{3}=-2\dfrac{1}{3}+\left(-1\dfrac{1}{3}\right)=-\left(2\dfrac{1}{3}+1\dfrac{1}{3}\right)\\\\=-\bigg[(2+1)+\left(\dfrac{1}{3}+\dfrac{1}{3}\right)\bigg]=-\left(3+\dfrac{1+1}{3}\right)\\\\=-3\dfrac{2}{3}](https://tex.z-dn.net/?f=-2%5Cdfrac%7B1%7D%7B3%7D-1%5Cdfrac%7B1%7D%7B3%7D%3D-2%5Cdfrac%7B1%7D%7B3%7D%2B%5Cleft%28-1%5Cdfrac%7B1%7D%7B3%7D%5Cright%29%3D-%5Cleft%282%5Cdfrac%7B1%7D%7B3%7D%2B1%5Cdfrac%7B1%7D%7B3%7D%5Cright%29%5C%5C%5C%5C%3D-%5Cbigg%5B%282%2B1%29%2B%5Cleft%28%5Cdfrac%7B1%7D%7B3%7D%2B%5Cdfrac%7B1%7D%7B3%7D%5Cright%29%5Cbigg%5D%3D-%5Cleft%283%2B%5Cdfrac%7B1%2B1%7D%7B3%7D%5Cright%29%5C%5C%5C%5C%3D-3%5Cdfrac%7B2%7D%7B3%7D)
Answer:5
Step-by-step explanation:
I said that because I just divide
Answer:
The zeros are

Step-by-step explanation:
We have been given the equation x^4-6x^2-7x-6=0
Use rational root theorem, we have






Again factor using the rational root test, we get

Using the zero product rule, we have

Therefore, the zeros are

Hey there!!
Given:
... A=3B+7C
Subtracting 7C on both sides:
... A-7C=3B
Dividing by B on both sides:
... (A-7C)/3=B
<em>Hope my answer helps!</em>
Answer:
Step-by-step explanation:
Next time, please share the possible answer choices.
a^2 - b^2 is "a difference with two terms."
So is x - y.