Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
Answer:
for this one b=49.458
Step-by-step explanation:
<u>Given</u>:
Let A denote the angle of the given triangle which measures ∠A = 81°
Let B denote the angle which measures ∠B = 40°
The length of the side a = x.
The length of the side b = 7 cm.
We need to determine the value of x.
<u>Value of x:</u>
The value of x can be determined using the law of sine formula.
Applying the law of sine, we have;
Substituting the values, we have;
Simplifying, we get;
Cross multiplying, we have;
Thus, the length of the side x is 10.8 cm.
Answer:
1/5
Step-by-step explanation:
You have to do whats in the parentheses first then you start doing to exponets from left to right then you would multiply then you would get your answer 1/5.
