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Alex_Xolod [135]
3 years ago
6

How many times does 5 go into 100

Mathematics
1 answer:
Rasek [7]3 years ago
7 0
<span>I believe in this item, we are asked to determine how many 5's should be added together in order to form 100. This is calculated by dividing 100 by 5. The answer by completing the operation would be equal to 20. Hence, the answer is 20. </span>
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Geometry- I need an answer for x and y.
elixir [45]

Answer:

x = 13sqrt(3) ft = 22.5 ft

y = 13 ft

Step-by-step explanation:

The triangle is a 30-60-90 right triangle.

The ratio of the lengths of the sides is

short leg : long leg : hypotenuse = 1 : sqrt(3) : 2

From the ratio above we see that the hypotenuse is twice the short leg.

The long leg is sqrt(3) times the short leg.

y = short leg

x = long leg

26 ft = hypotenuse

y = 26 ft/2 = 13 ft

x = 13 ft * sqrt(3) = 13sqrt(3) ft = 22.5 ft

6 0
2 years ago
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Which option for college funding can parents start when children are still very young? College savings account scholarship work-
kap26 [50]

Answer:

Your answer would be A: "college savings account."

Step-by-step explanation:

Got it right on edge.

6 0
3 years ago
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A right triangle and some of his measurements are shown in the diagram based on the measurements shown in the diagram what is T
True [87]
I don’t really know this exact method
3 0
2 years ago
Which lines is a parallel to the line y=1/2x+5 and passes through the point (-2,1)?
Archy [21]

Answer:

The answer is: y = 1/2x + 2

Step-by-step explanation:

Given equation: y = 1/2x + 5

Given point: (-2, 1)

The slope of the given line is 1/2. Parallel lines have the same slope.

Use the point slope form and solve for y:

y - y1 = m(x - x1)

y - 1 = 1/2(x - (-2))

y - 1 = 1/2(x + 2)

y - 1 = 1/2x + 1/2 * 2

y - 1 = 1/2x + 1

y = 1/2x + 2

Proof:

f(-2) = 1/2(-2) + 2

= -1 + 2

= 1, giving point (-2, 1)

Hope this helps!! Have an Awesome Day!! :-)

5 0
3 years ago
Simplify the following expression. cot^2x secx-cosx
Solnce55 [7]

ANSWER

\cos(x)   \cot ^{2} (x)

EXPLANATION

The given expression is;

\cot^{2} (x)  \sec(x)  -  \cos(x)

Change everything to

\sin(x)

and

\cos(x)

This implies that,

\frac{ \cos^{2} (x) }{ \sin^{2} (x) }  \times ( \frac{1}{ \cos(x) } )-  \cos(x)

Cancel the common factors,

\frac{ \cos(x) }{ \sin^{2} (x) }  \times ( \frac{1}{1} )-  \cos(x)

\frac{ \cos(x) }{ \sin^{2} (x) }-  \cos(x)

\frac{ \cos(x)  -  \sin ^{2} (x)  \cos(x) }{ \sin^{2} (x) }

= \frac{ \cos(x)(1  -  \sin ^{2} (x) ) }{ \sin^{2} (x) }

= \frac{ \cos(x)(\cos^{2} (x) ) }{ \sin^{2} (x) }

= \cos(x)  \cot^{2} (x)

6 0
2 years ago
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